本文介绍了将字符串拆分为迭代器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
python是否有内置(意味着在标准库中)对产生迭代器而不是列表的字符串进行拆分?我在考虑使用非常长的字符串而不需要消耗大部分字符串。
Does python have a build-in (meaning in the standard libraries) to do a split on strings that produces an iterator rather than a list? I have in mind working on very long strings and not needing to consume most of the string.
推荐答案不直接拆分字符串,但 re 模块有 re.finditer() (以及任何已编译的正则表达式上相应的 finditer()方法) 。
Not directly splitting strings as such, but the re module has re.finditer() (and corresponding finditer() method on any compiled regular expression).
@Zero要求举个例子:
@Zero asked for an example:
>>> import re >>> s = "The quick brown\nfox" >>> for m in re.finditer('\S+', s): ... print(m.span(), m.group(0)) ... (0, 3) The (4, 9) quick (13, 18) brown (19, 22) fox更多推荐
将字符串拆分为迭代器
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