遍历两个不同长度的列表

本文介绍了遍历两个不同长度的列表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有以下两个列表:

nums = [1, 2, 3, 4, 5, 6, 7, 8] ltrs = ['a', 'b', 'c', 'd'] for x, y in nums, ltrs: print(x, y)

出现以下错误

c:\Python35\Scripts>python listtest.py Traceback (most recent call last): File "listtest.py", line 5, in <module> for x, y in nums, ltrs: ValueError: too many values to unpack (expected 2)

我希望输出为:

1a，2b，3c，4d，5、6、7、8

1a, 2b, 3c, 4d, 5, 6, 7, 8

从我阅读的内容来看， zip 方法仅在两个列表的长度相同时才起作用，对于不同长度的列表，我的选择是什么?

From what I have read the zip method will only work if the two lists are the same length, what are my options with lists of different lengths?

推荐答案

您可以将 itertools.zip_longest 用于Python3:

You can use itertools.zip_longest for Python3:

import itertools nums = [1, 2, 3, 4, 5, 6, 7, 8] ltrs = ['a', 'b', 'c', 'd'] final_list = [''.join([str(c) if isinstance(c, int) else c for c in [i for i in b if i is not None]]) for b in itertools.zip_longest(nums, ltrs)]

输出:

['1a', '2b', '3c', '4d', '5', '6', '7', '8']