如何检查一个数组是否是JavaScript中另一个数组的子集?

本文介绍了如何检查一个数组是否是JavaScript中另一个数组的子集?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

假设我有两个数组，

var PlayerOne = ['B', 'C', 'A', 'D']; var PlayerTwo = ['D', 'C'];

使用JavaScript检查arrayTwo是否为arrayOne的子集的最佳方法是什么?

What is the best way to check if arrayTwo is subset of arrayOne using javascript?

原因:我试图整理井字游戏的基本逻辑，并陷入了中间.无论如何，这是我的代码...谢谢！！

The reason: I was trying to sort out the basic logic for a game Tic tac toe, and got stuck in the middle. Here's my code anyway... Thanks heaps!

var TicTacToe = { PlayerOne: ['D','A', 'B', 'C'], PlayerTwo: [], WinOptions: { WinOne: ['A', 'B', 'C'], WinTwo: ['A', 'D', 'G'], WinThree: ['G', 'H', 'I'], WinFour: ['C', 'F', 'I'], WinFive: ['B', 'E', 'H'], WinSix: ['D', 'E', 'F'], WinSeven: ['A', 'E', 'I'], WinEight: ['C', 'E', 'G'] }, WinTicTacToe: function(){ var WinOptions = this.WinOptions; var PlayerOne = this.PlayerOne; var PlayerTwo = this.PlayerTwo; var Win = []; for (var key in WinOptions) { var EachWinOptions = WinOptions[key]; for (var i = 0; i < EachWinOptions.length; i++) { if (PlayerOne.includes(EachWinOptions[i])) { (got stuck here...) } } // if (PlayerOne.length < WinOptions[key]) { // return false; // } // if (PlayerTwo.length < WinOptions[key]) { // return false; // } // // if (PlayerOne === WinOptions[key].sort().join()) { // console.log("PlayerOne has Won!"); // } // if (PlayerTwo === WinOptions[key].sort().join()) { // console.log("PlayerTwo has Won!"); // } (tried this method but it turned out to be the wrong logic.) } }, }; TicTacToe.WinTicTacToe();

推荐答案

这是正确的解决方案:

使用ES7 ( ECMAScript 2016 ):

Using ES7 (ECMAScript 2016):

const result = PlayerTwo.every(val => PlayerOne.includes(val));

代码段:

const PlayerOne = ['B', 'C', 'A', 'D']; const PlayerTwo = ['D', 'C']; const result = PlayerTwo.every(val => PlayerOne.includes(val)); console.log(result);

使用ES5 ( ECMAScript 2009 ):

Using ES5 (ECMAScript 2009):

var result = PlayerTwo.every(function(val) { return PlayerOne.indexOf(val) >= 0; });

代码段:

var PlayerOne = ['B', 'C', 'A', 'D']; var PlayerTwo = ['D', 'C']; var result = PlayerTwo.every(function(val) { return PlayerOne.indexOf(val) >= 0; }); console.log(result);