SlugField中的连字符

本文介绍了SlugField中的连字符的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

所以，这是一个奇怪的错误，当我打开带有连字符的URL在SlugField，虽然SlugField支持连字符，如文档中所示。错误：

找不到页面（404）请求方法：GET 请求URL：http： /127.0.0.1:8003/dumpster-rental-prices 使用dumpster.urls中定义的URLconf，Django按以下顺序尝试了这些URL模式： ^ admin / ^（？P< ; slug> \w +）/ $ 当前URL，dumpster-rental-prices与这些没有匹配。

如果我将文章的小块更改为dumpster_rental_prices - url 127.0.0.1:8003/dumpster_rental_prices打开

这是博客应用的models.py：

从django.db导入模型 class Post（models.Model）： title = models.CharField（max_length = 100） body = models.TextField（max_length = 5000） slug = models.SlugField（max_length = 100） def __unicode __（self）： return self.title

这是博客foder中的urls.py：

from django .conf.urls import pattern，include，url from django.views.generic import DetailView，ListView from blog.models import Post from django.contrib import admin admin.autodiscover（） urlpatterns = patterns（''， url（r'^（？P< slug> \w +）/ $'， DetailView .as_view（ model = Post，t emplate_name ='detail.html'））， ）

谢谢提前为您的帮助。

解决方案

问题是您的正则表达式 - \w 只匹配字母数字字符和下划线。如果你想匹配连字符，你需要像 r'^（？P< slug> [\w - ] +）/ $ 的东西。

There is a strange error when i open a URL with hyphens in the slug, though SlugField supports hyphens in it as indicated in documentation.

So, this is the error:

Page not found (404) Request Method: GET Request URL: 127.0.0.1:8003/dumpster-rental-prices Using the URLconf defined in dumpster.urls, Django tried these URL patterns, in this order: ^admin/ ^(?P<slug>\w+)/$ The current URL, dumpster-rental-prices, didn't match any of these.

If i change the slug of the article to dumpster_rental_prices - the url 127.0.0.1:8003/dumpster_rental_prices opens fine.

This is models.py of blog app:

from django.db import models class Post(models.Model): title = models.CharField(max_length = 100) body = models.TextField(max_length = 5000) slug = models.SlugField(max_length = 100) def __unicode__(self): return self.title

This is urls.py in blog foder:

from django.conf.urls import patterns, include, url from django.views.generic import DetailView, ListView from blog.models import Post from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^(?P<slug>\w+)/$', DetailView.as_view( model=Post, template_name='detail.html')), )

Thank you in advance for your help.

解决方案

The problem is your regex - \w only matches alphanumerical characters and underscores. You need something like r'^(?P<slug>[\w-]+)/$ if you want to match hyphens as well.