计算Python字符串的唯一字符总数

本文介绍了计算Python字符串的唯一字符总数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

对于上述问题，我深陷其中.到目前为止，我想出的代码是:

For my question above, I'm terribly stuck. So far, the code I have come up with is:

def count_bases(): get_user_input() amountA=get_user_input.count('A') if amountA == 0: print("wrong") else: print ("right",amountA) def get_user_input(): one = input("Please enter DNA bases: ") two=list(one) print(two)

我的思路是我首先: 1.要求用户输入DNA碱基(ATCG) 2.将用户输入更改为列表 3.回到主要(count_bases)函数，我计算'A'，'T'，'C'，'G'的数量 4.对4个不同的基数使用4条if-else语句.

My line of thinking is that I first: 1. Ask user to enter the DNA bases (ATCG) 2. Change the user input into a list 3. Going back to the main (count_bases) function, I count the number of 'A', 'T', 'C', 'G' 4. Use 4 if-else statements for the four different bases.

到目前为止，我的代码仅适用于列表中用户输入的输出.之后，会弹出一个错误. 如果有人可以向我指出正确的道路，请多加赞赏！ 谢谢.

So far, my code only works up to the output of the user's input into a list. After that, an error just pops up. Appreciate it if someone can point the right path out to me! Thanks.

推荐答案

您的函数get_user_input()没有返回值

get_user_input.count('A')包含一个函数调用，如果没有括号，它将无法使用.正确:get_user_input().count('A')

如评论中所述，get_user_input()仅应调用一次，因为用户输入将通过input()函数在每次调用时收集.

Your function get_user_input() has no return value

get_user_input.count('A') contains a function call, it will not work without parenthesis. Correct: get_user_input().count('A')

As mentioned in the comments, get_user_input() should only be called once since the users input will be collected at each call via the input() function.

这应该有效:

def count_bases(): char_list = get_user_input() for char in 'ATCG': char_count = char_list.count(char) if char_count < 1: print(char + " not found") else: print(char + " count: " + str(char_count)) def get_user_input(): one = input("Please enter DNA bases: ") two=list(one) return two