一元减号和浮充转换的组合

本文介绍了一元减号和浮充转换的组合的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

考虑下面的C语句：

unsigned long x = 1; float a = -x; double b = -x;

我希望一元减术语，以产生一个unsigned long值等于ULONG_MAX和A和B分别设为ULONG_MAX的单，双precision重新presentations。

I would expect the unary minus term to yield an unsigned long value equal to ULONG_MAX and a and b to be set to single and double precision representations of ULONG_MAX, respectively.

这是结果我与32位Linux，并与64位Linux的英特尔和PGI编译器GCC 4.4.7获得。与海湾合作委员会的64位Linux（测试版本4.4.7，4.7.2和4.8.0，都与-O0和-O2），然而，双变量B的预期值，但浮动等于-1来代替。

This is the result I obtain with gcc 4.4.7 on 32-bit Linux and with the Intel and PGI compilers on 64-bit Linux. With gcc (tested versions 4.4.7, 4.7.2 and 4.8.0, both with -O0 and -O2) on 64-bit Linux, however, the double variable b has the expected value, but float a becomes equal to -1 instead.

相反，下面的语句将A和B都设置为浮动ULONG_MAX点重新presentations所有的编译器和系统我测试：

By contrast, the following statements will set both a and b to floating point representations of ULONG_MAX on all compilers and systems I tested:

unsigned long x = 1; unsigned long y = -x; float a = y; double b = y;

如果我使用unsigned int类型，而不是无符号长的，我得到的所有系统上的预期的结果了。

If I use unsigned int instead of unsigned long, I get the expected result on all systems, too.

这是某种不确定的行为或编译器错误？

Is this some kind of undefined behaviour or a compiler error?

推荐答案

这是由于错误的GCC - 否定之前的类型转换发生

This is due to a bug in GCC -- the type conversion happens before the negation.

这个问题似乎已经存在了一段时间。 错误55771 - 否定与类型转换错误交换

The issue seems to be have been around for a while. Bug 55771 - Negation and type conversion incorrectly exchanged

在第二个例子中，否定类型转换之前发生。因此，你看到预期的效果。

In your second example, the negation happens before the type conversion. As such, you see expected results.