查找总和最小的子数组的索引

本文介绍了查找总和最小的子数组的索引的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

给出一个长度为n的数组，该数组带有整数(可以是负数或正数).找到子数组的开始和结束索引，并尽可能减少总和.

Given an array of length n, with integers(can be negative or positive). Find the starting and ending index of the subarray with minimum sum possible.

推荐答案

正如您所指定的，这是关于Kadanes算法的，很容易找到很多有关它的参考. GeeksForGeeks:最小和连续子数组请对该算法进行解释并提供实现几种语言.

As you specified this is about Kadanes Algorithm, it is easy to find a lot of references about it. GeeksForGeeks : Smallest sum contiguous subarray kindly explains about the algorithm and provides implementations in a few languages.

基于 python 代码的问题，我对其进行了修改，以返回开始/结束索引而不是总和值.这个想法是保持范围索引和总和值.

Based on the python code from that page, I have revised it to return begin/end indices rather than the sum value. The idea is keeping the range indices along with the sum value.

import sys def smallestSumSubarr(arr, n): min_ending_here = sys.maxint min_so_far = sys.maxint min_so_far_range = (-1, 0) # save indices for i in range(n): if (min_ending_here > 0): min_ending_here = arr[i] min_ending_here_range = (i, i) # start over else: min_ending_here += arr[i] min_ending_here_range = (min_so_far_range[0], i) # extend the range if min_so_far > min_ending_here: # update both value and range min_so_far = min_ending_here min_so_far_range = min_ending_here_range return min_so_far_range # return range instead of value # Usage arr = [3, -4, 2, -3, -1, 7, -5] n = len(arr) print "Smallest sum range(inclusive): ", smallestSumSubarr(arr, n)

在STDOUT上，您将看到

On STDOUT, you will see

Smallest sum range(inclusive): (1, 4)