如何按给定索引处的元素对列表/元组的列表/元组进行排序?

本文介绍了如何按给定索引处的元素对列表/元组的列表/元组进行排序?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我在列表列表或元组列表中都有一些数据，如下所示:

I have some data either in a list of lists or a list of tuples, like this:

data = [[1,2,3], [4,5,6], [7,8,9]] data = [(1,2,3), (4,5,6), (7,8,9)]

我想按子集中的第二个元素排序.意思是，按2,5,8排序，其中2来自(1,2,3)，5来自(4,5,6).常见的做法是什么?我应该在列表中存储元组还是列表?

And I want to sort by the 2nd element in the subset. Meaning, sorting by 2,5,8 where 2 is from (1,2,3), 5 is from (4,5,6). What is the common way to do this? Should I store tuples or lists in my list?

推荐答案

sorted_by_second = sorted(data, key=lambda tup: tup[1])

或:

data.sort(key=lambda tup: tup[1]) # sorts in place