是否有理由我们无法迭代“反向范围”？在红宝石？

本文介绍了是否有理由我们无法迭代“反向范围”？在红宝石？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我尝试使用范围和每个向后迭代：

I tried to iterate backwards with using a Range and each:

(4..0).each do |i| puts i end ==> 4..0

通过 0..4 写下数字。在另一个范围 r = 4..0 似乎没问题， r.first == 4 ， r.last == 0 。

Iteration through 0..4 writes the numbers. On the other Range r = 4..0 seems to be ok, r.first == 4, r.last == 0.

我觉得上面的结构不能产生预期的结果似乎很奇怪。这是什么原因？当这种行为合理时会出现什么情况？

It seems to be strange to me that the construct above does not produce the expected result. What is the a reason for that? What are the situations when this behaviour is reasonable?

推荐答案

范围就是：由开始和结束定义的东西，而不是按其内容。在一般情况下，迭代范围并不真正有意义。例如，考虑如何迭代两个日期产生的范围。你会白天迭代吗？按月？按年？一周？它没有明确定义。 IMO，它允许转发范围这一事实应仅被视为一种便利方法。

A range is just that: something defined by its start and end, not by its contents. "Iterating" over a range doesn't really make sense in a general case. Consider, for example, how you would "iterate" over the range produced by two dates. Would you iterate by day? by month? by year? by week? It's not well-defined. IMO, the fact that it's allowed for forward ranges should be viewed as a convenience method only.

如果你想在这样的范围内向后迭代，你可以随时使用 downto ：

If you want to iterate backwards over a range like that, you can always use downto:

$ r = 10..6 => 10..6 $ (r.first).downto(r.last).each { |i| puts i } 10 9 8 7 6

以下是 更多想法 来自其他人，为什么很难同时允许迭代并始终​​处理反向范围。

Here are some more thoughts from others on why it's tough to both allow iteration and consistently deal with reverse-ranges.