用于从 Python 到 Ruby 查找集合的所有分区的转换函数

编程入门行业动态更新时间:2024-10-22 18:42:20

本文介绍了用于从 Python 到 Ruby 查找集合的所有分区的转换函数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

我有以下 python 函数来递归查找集合的所有分区:

I have the following python function to recursively find all partitions of a set:

def partitions(set_): if not set_: yield [] return for i in xrange(2**len(set_)/2): parts = [set(), set()] for item in set_: parts[i&1].add(item) i >>= 1 for b in partitions(parts[1]): yield [parts[0]]+b for p in partitions(["a", "b", "c", "d"]): print(p)

有人可以帮我把它翻译成 ruby 吗?这是我目前所拥有的:

Can someone help me to translate this into ruby? This is what I have so far:

def partitions(set) if not set yield [] return end (0...2**set.size/2).each { |i| parts = [Set.new, Set.new] set.each { |item| parts[i&1] << item i >>= 1 } partitions(parts[1]).each { |b| yield [parts[0]] << b } } end p partitions([1, 2, 3, 4].to_set)

我收到错误LocalJumpError: no block given".我猜这是因为 yield 函数在 Python 和 Ruby 中的工作方式不同.

I get the error "LocalJumpError: no block given". I guess this is because the yield functions work differently in Python and Ruby.

推荐答案

#!/usr/bin/ruby1.8 def partitions(set) yield [] if set.empty? (0 ... 2 ** set.size / 2).each do |i| parts = [[], []] set.each do |item| parts[i & 1] << item i >>= 1 end partitions(parts[1]) do |b| result = [parts[0]] + b result = result.reject do |e| e.empty? end yield result end end end partitions([1, 2, 3, 4]) do |e| p e end # => [[1, 2, 3, 4]] # => [[2, 3, 4], [1]] # => [[1, 3, 4], [2]] # => [[3, 4], [1, 2]] # => [[3, 4], [2], [1]] # => [[1, 2, 4], [3]] # => [[2, 4], [1, 3]] # => [[2, 4], [3], [1]] # => [[1, 4], [2, 3]] # => [[1, 4], [3], [2]] # => [[4], [1, 2, 3]] # => [[4], [2, 3], [1]] # => [[4], [1, 3], [2]] # => [[4], [3], [1, 2]] # => [[4], [3], [2], [1]]

有什么不同: