从列表中获取随机元素的Groovy方法

本文介绍了从列表中获取随机元素的Groovy方法的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

Groovy是管理集合的强大工具.我有一个像这样的清单:

Groovy is extremely powerful managing collections. I have a list like this one:

def nameList = ["Jon", "Mike", "Alexia"]

我想做的是迭代10次，从第一个列表中获得10个名字随机的人.

What I am trying to do is iterating 10 times to get ten people with a random name from the first list.

10.times{ Person person = new Person( name: nameList.get() //I WANT TO GET A RANDOM NAME FROM THE LIST ) }

由于两个明显的原因，此方法不起作用，我没有在nameList.get中添加任何索引，也没有创建10个不同的Person对象.

This is not working for two obvious reasons, I am not adding any index in my nameList.get and I am not creating 10 different Person objects.

如何使用groovy从名称列表中获取随机元素?

我可以使用groovy的collections属性以简单的方式创建一个包含10个人的随机名称列表吗?

推荐答案

只需使用Java方法Collections.shuffle()之类的

Just use the Java method Collections.shuffle() like

class Person { def name } def nameList = ["Jon", "Mike", "Alexia"] 10.times { Collections.shuffle nameList Person person = new Person( name: nameList.first() ) println person.name }

或使用类似的随机索引

class Person { def name } def nameList = ["Jon", "Mike", "Alexia"] def nameListSize = nameList.size() def r = new Random() 10.times { Person person = new Person( name: nameList.get(r.nextInt(nameListSize)) ) println person.name }