一次迭代一个数组2个项目

本文介绍了一次迭代一个数组2个项目的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个类似 {a，b，c，d} 的字符串数组。每两个连续的项是成对的，我想迭代数组，并能够将两个字符串一起考虑。目前我正在考虑使用循环和计数来计算我在迭代中的位置，但有更简单/更好的方法吗？

I have a string array that looks something like {"a","b","c","d"}. Each two consecutive items are pairs and I want to iterate through the array and be able to consider the two strings together. Currently I'm thinking of having a loop and a count to work out where I am in the iteration but is there a simpler/better way?

推荐答案

for (int i=0 ; i<a.length ; i+=2) { String first = a[i]; String second = a[i+1]; ... }

如果数组由来电者提供，那么你可能想要处理a.length不均匀的情况。

If the array is provided by a caller, then you might want to handle the case where a.length is not even.