如何在MIPS中获得LSB位?

本文介绍了如何在MIPS中获得LSB位?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

在MIPS中，是否存在一种简短的方法来检查/获取32位整数中的最低有效位?显然，它是为奇数设置的，并且检查整数是否为奇数甚至是偶数的算法可以对此做出决定.但是我只是想知道有没有更好的方法来做到这一点...

Is there a short way to check/get for least significant bit in a 32-bit integer, in MIPS? It is obviously set for the odd numbers and an algorithm which checks for the whole number is odd or even can decide for this. But I just wonder is there a better way to do this...

推荐答案

andi $t0, $s0, 1将获得$s0的最低有效位并将其放入$t0.

andi $t0, $s0, 1 will get the least significant bit of $s0 and put it in $t0.