如何仅获取Wikidata中特定类别的所有属性?

编程入门行业动态更新时间:2024-10-10 06:20:43

本文介绍了如何仅获取Wikidata中特定类别的所有属性?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

是否存在rdf数据/其他格式，可让我获取类别中可能存在的所有属性，例如人，那么我应该返回属性，例如性别，出生日期

Is there an rdf data/other format that allow me to get all the properties that can exist in a category e.g. Person, then I should be returned properties like sex, date of birth

如何在 query.wikidata/上查询此信息?

我想要的是这个 www.wikidata/wiki/Wikidata:List_of_properties/Summary_table 但是，有没有更好的格式呢?我想以编程方式访问

What i want is this www.wikidata/wiki/Wikidata:List_of_properties/Summary_table But is there a better format for this ? I want to access programmatically

更新

此查询太重，导致超时.

This query is too heavy, causes timeout.

SELECT ?p ?attName WHERE { ?q wdt:P31 wd:Q5. ?q ?p ?statement. ?realAtt wikibase:claim ?p. ?realAtt rdfs:label ?attName. FILTER(((LANG(?attName)) = "en") || ((LANG(?attName)) = "")) } GROUP BY ?p ?attName

我必须指定实体，例如到巴拉克·奥巴马(Barrack Obama)，它就可以了，但这并不能给我所有可能的特性.

I must specify the entity, e.g. to Barrack Obama then it works, but this does not give me the all possible properties.

SELECT ?p ?attName WHERE { BIND(wd:Q76 AS ?q) ?q wdt:P31 wd:Q5. ?q ?p ?statement. ?realAtt wikibase:claim ?p. ?realAtt rdfs:label ?attName. FILTER(((LANG(?attName)) = "en") || ((LANG(?attName)) = "")) } GROUP BY ?p ?attName

推荐答案

您链接到的页面是由漫游器创建的.如果您需要了解漫游器的工作方式，请与 BetaBot 操作员联系.

The page you have linked to is created by a bot. Contact the BetaBot operator, if you need to know how the bot works.

也许该机器人依赖 wd:P1963 属性:

Perhaps the bot relies on the wd:P1963 property:

SELECT ?property ?propertyLabel { VALUES (?class) {(wd:Q5)} ?class wdt:P1963 ?property SERVICE wikibase:label { bd:serviceParam wikibase:language "en" } } ORDER BY ASC(xsd:integer(strafter(str(?property), concat(str(wd:), "P"))))

上述查询返回 49个结果.

The above query returns 49 results.

我建议您依靠属性页中的类型约束:

I'd suggest you rely on type constraints from property pages:

SELECT ?property ?propertyLabel { VALUES (?class) {(wd:Q5)} ?property a wikibase:Property . ?property p:P2302 [ ps:P2302 wd:Q21503250 ; pq:P2309 wd:Q21503252 ; pq:P2308 ?class ] . SERVICE wikibase:label { bd:serviceParam wikibase:language "en" } } ORDER BY ASC(xsd:integer(strafter(str(?property), concat(str(wd:), "P"))))

上述查询返回 700个结果.

The above query returns 700 results.

您的问题中的第一个查询适用于相对较小的类，例如e. G. wd:Q6256(国家").在公共端点上，不可能使查询适用于大型类.

The first query from your question works fine for relatively small classes, e. g. wd:Q6256 ('country'). On the public endpoint, it is not possible to make the query work for large classes.

但是，您可以将查询分为几部分.在Python中:

However, you could split the query into small parts. In Python:

from wdqs import Client from time import sleep client = Client() result = client.query("SELECT (count(?p) AS ?c) {?p a wikibase:Property}") count = int(result[0]["c"]) offset = 0 limit = 50 possible = [] while offset <= count: props = client.query(""" SELECT ?property WHERE { hint:Query hint:optimizer "None" . { SELECT ?property { ?property a wikibase:Property . } ORDER BY ?property OFFSET %s LIMIT %s } ?property wikibase:directClaim ?wdt. FILTER EXISTS { ?human ?wdt [] ; wdt:P31 wd:Q5 . hint:Group hint:maxParallel 501 . } hint:Query hint:filterExists "SubQueryLimitOne" . # SERVICE wikibase:label { bd:serviceParam wikibase:language "en" } } """ % (offset, limit)) for prop in props: possible.append(prop['property']) offset += limit print (len(possible), min(offset, count)) sleep(0.25)