使用 Racket 实现 SICP 评估器

本文介绍了使用 Racket 实现 SICP 评估器的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在研究 4.1.4 Running the Evaluator as a Program 的元循环计算器，使用 Racket 构建它:

I'm working on metacircular evaluator of 4.1.4 Running the Evaluator as a Program, building which with Racket:

#lang racket (require (combine-in rnrs/base-6 rnrs/mutable-pairs-6)) (define (evaluate exp) (cond ; ... ((definition? exp) (display exp) (display " is a definition\n")) ; ... (else (display exp) (display " is something else\n")))) (define (definition? exp) (tagged-list? exp 'define)) (define (tagged-list? exp tag) (if (pair? exp) (eq? (car exp) tag) false)) (define (driver-loop) (let ((input (read))) (let ((output (evaluate input))) output)) (driver-loop)) (driver-loop)

在成功读取DrRacket中的输入框后，我输入(define a 0)，结果是:

After getting a box that reads input in DrRacket successfully, I type in (define a 0) and it turn out:

(定义一个 0)是别的东西

如果我删除它可以被识别

It could be recognised if I remove

(require (combine-in rnrs/base-6 rnrs/mutable-pairs-6))

但没有它我将无法调用 set-car! 或 set-cdr!.set- 函数有替代方法吗?

But without which I wouldn't be able to call set-car! or set-cdr!. Is there an alternative for set- function?

或者我可以选择从 rnrs/base-6 和 rnrs/mutable-pairs-6 导入什么?

Or could I choose what to import from rnrs/base-6 and rnrs/mutable-pairs-6 ?

推荐答案

这里是错误:

(require (combine-in rnrs/base-6 rnrs/mutable-pairs-6))

包 rnrs/base-6 和 rnrs/mutable-pairs-6 带来了一些不可预测的变化 cons(以及 car, cdr) 前导 (define a 0) 没有被 definition 捕获?

Package rnrs/base-6 and rnrs/mutable-pairs-6 bring in something unpredicted that change cons(as well as car, cdr) leading (define a 0) not been caught by definition?

解决方案:

(require (only-in (combine-in rnrs/base-6 rnrs/mutable-pairs-6) set-car! set-cdr!))

始终将 only-in 放在 require 中以避免任何不需要的绑定.

Always put only-in in require to avoid any unwanted binding.