Solr：使用Block Join Children Query Parser

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目前，我按照这里所述评估了Block Join Children Query Parser 。

因此我创建了以下集合：

Therefore I have created the following collection:

curl "localhost:8983/solr/admin/collections?action=CREATE&name=nestedPerson&numShards=6"`

然后我插入了这两个文件：

Then I have inserted these two documents:

curl localhost:8983/solr/nestedPerson/update?commitWithin=3000 -d '<add> <doc> <field name="id">p1</field> <field name="deceased">false</field> <doc> <field name="id">c1</field> <field name="firstName">Bob</field> </doc> </doc> <doc> <field name="id">p2</field> <field name="deceased">true</field> <doc> <field name="id">c2</field> <field name="firstName">Max</field> </doc> </doc> </add>'

现在我发出此查询：

{!child of="id:p1"}firstName:Bob

不幸的是，这导致了这个错误：

Unfortunately this results in this error:

"msg": "Parent query yields document which is not matched by parents filter, docID=0",

父查询如何（我想部分 id：p1 意味着产生一个与过滤器不匹配的文件？

How can the parent query (I guess that the part id:p1 is meant) yield a document that is not matched by the filter?

推荐答案

再看一下你再次提到的Solr Wiki 这里。请注意以下内容：

Take a look at the Solr Wiki that you refer to again here. Note the following:

此解析器的语法为：q = {！child of =< allParents>}< someParents>。参数allParents是仅匹配父文档的过滤器

在您的示例中，查询是 {！child of = ID：P1}姓：鲍勃。字段 id 用于< allParents> ，但 id 包含在父文档和子文档中。

In your example, the query is {!child of="id:p1"}firstName:Bob. The field id as used in<allParents>, but id is contained in both parent and child documents.

您需要引入一个只有父文档的字段，例如< field name =content_type> parentDocument< / field>来自wiki的。一旦所有父文档（以及仅父文档）具有此字段，您可以将查询提交为：

You need to introduce a field that only parent documents have, such as <field name="content_type">parentDocument</field> from the wiki. Once all parent documents (and only parent documents) have this field, you could submit the query as:

q = {！parent which = content_type：parentDocument} firstName：Bob

这将匹配 firstName：Bob 并归还他们的父母。以类似的方式，使用 q = {！child of =< allParents>}< someParents> 来匹配父文档并返回他们的孩子。

This would match child documents for firstName:Bob and return their parents. In a similar fashion, use q={!child of=<allParents>}<someParents> to match parent documents and return their children.