如何从多个文件访问内容

本文介绍了如何从多个文件访问内容的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

有什么方法可以添加多个文件的内容，然后将合并的值放入一个文件中?

Is there any way that I can add the content of multiple files then put the combined values into one file?

我目前正在尝试:

$start_tr = include 'include_all_items/item_input_start_tr.php' ; $img_start = include 'include_all_items/item_input_img_start.php' ; $img_link = include 'include_all_items/item_input_img_link.php' ; $img_end = include 'include_all_items/item_input_img_end.php' ; $newcontent = "$start_tr $link $img_start $_POST[img_link] $img_end "; $content = $newcontent.file_get_contents('../../include/itemputer.php'); file_put_contents('../../include/itemputer.php', $content);

推荐答案

include 用于代码，而不用于 content .您必须使用 file_get_contents 来保存返回的值. include 不会赋予您该值.

include is for code, not for content. In your case you have to use file_get_contents so you can save the returned value. include will not give you that value.

include()

处理返回值:include失败时返回FALSE并发出警告.成功包含，除非被包含的文件覆盖，否则返回1.

Handling Returns: include returns FALSE on failure and raises a warning. Successful includes, unless overridden by the included file, return 1.

$start_tr = file_get_contents('include_all_items/item_input_start_tr.php'); $img_start = file_get_contents('include_all_items/item_input_img_start.php'); $img_link = file_get_contents('include_all_items/item_input_img_link.php'); $img_end = file_get_contents('include_all_items/item_input_img_end.php');

现在，您可以像以前一样使用变量.

Now you can use your variable like you did.

$newcontent = "$start_tr $link $img_start $_POST[img_link] $img_end ";