通过路径获取Alfresco NodeRef（实时，安全的竞争条件）

本文介绍了通过路径获取Alfresco NodeRef（实时，安全的竞争条件）的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想获取存储在Alfresco中的文档（或空间）的NodeRef。

I want to get the NodeRef of a document (or space) stored in Alfresco.

我的代码是Java，在Alfresco中运行（例如在AMP中） ）。

My code is in Java, running within Alfresco (for instance in an AMP).

我的代码需要在出现竞争条件时保持安全，例如，它必须找到之前创建的第二个节点。在这种情况下，不能使用常用方法（基于搜索）。

My code needs to be safe against race conditions, for instance it must find nodes that have been created a second before. In this context, the usual methods (search-based) can not be used.

怎么办？

推荐答案

您需要避免碰触任何东西SOLR，如那些API最终都是一致的

You need to avoid anything that touches SOLR, as those APIs are only Eventually Consistent

具体来说，您需要一个基于 canned的API查询。您的用例主要是 NodeService.getChildAssocs 和 NodeService.getChildByName 。某些 FileFolderService

Specifically, you need an API that's based on canned queries. The main ones for your use-case are NodeService.getChildAssocs and NodeService.getChildByName. Some of FileFolderService will work immediately too

您最好的选择是将路径拆分为多个组件，然后通过它进行递归/循环下降。根据要使用名称（ cm：name ）还是QName（基于asoc），您将使用两个 NodeService之一方法

Your best bet would be to split a path into components, then do a recursive / looping descent through it. Depending on if you want it by Name (cm:name) or QName (based on the assoc), you'd use one of the two NodeService methods

例如（未完全测试...）

eg (not fully tested...)

String[] parts = path.split("\\/"); NodeRef nodeRef = nodeService.getRootNode(StoreRef.STORE_REF_WORKSPACE_SPACESSTORE); for (String name : parts) { NodeRef child = nodeService.getChildByName(nodeRef, ContentModel.ASSOC_CONTAINS, name); if (child == null) throw new Exception("Path part not found "+name+" in "+path+" at "+nodeRef); nodeRef = child; } return nodeRef;