我的C程式贴在下面。在bash中,程序打印char is,不打印Ω。我的区域设置都是en_US.utf8。
My C program is pasted below. In bash, the program print "char is ", Ω is not printed. My locale are all en_US.utf8.
#include <stdio.h> #include <wchar.h> #include <stdlib.h> int main() { int r; wchar_t myChar1 = L'Ω'; r = wprintf(L"char is %c\n", myChar1); }推荐答案
显然,编译器将omega从UTF-8转换为UNICODE,但不知何故,libc会把它弄乱。
This was quite interesting. Apparently the compiler translates the omega from UTF-8 to UNICODE but somehow the libc messes it up.
首先:%c -format说明符需要 char (即使在 wprintf -version),所以你必须指定%lc (因此%ls 字符串)。
First of all: the %c-format specifier expects a char (even in the wprintf-version) so you have to specify %lc (and therefore %ls for strings).
其次,如果你运行你的代码,语言环境设置为 C 环境)。您必须致电 setlocale 空字符串从环境中获取语言环境,所以libc再次很高兴。
Secondly if you run your code like that the locale is set to C (it isn't automatically taken from the environment). You have to call setlocale with an empty string to take the locale from the environment, so the libc is happy again.
#include <stdio.h> #include <wchar.h> #include <stdlib.h> #include <locale.h> int main() { int r; wchar_t myChar1 = L'Ω'; setlocale(LC_CTYPE, ""); r = wprintf(L"char is %lc (%x)\n", myChar1, myChar1); }更多推荐
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