黑莓GPS获取当前位置的地址？

编程入门行业动态更新时间:2024-10-11 15:19:23

本文介绍了黑莓GPS获取当前位置的地址？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

您好，我是新来的黑莓应用程序development.I想得到当前GPS位置detail.I已经顺利拿到了纬度和经度，但我不知道如何获得当前address.can任何人给我一个样品？PLS感谢在前进。

Hi i am new to blackberry application development.I want to get current gps location detail.I had successfully got the latitude and longitude but i dont know how to get the current address.can any one give me a sample?Pls thanks in advance.

推荐答案

您可以使用谷歌地图来解决你的问题，如果你有一个lattitude和经度要求谷歌地图会根据您的选择返回JSON（或XML）。

You can use Google map to resolve your issue, Google map will return a JSON (or XML) according to your choice if you request with a lattitude and longitude.

网址是： maps.google/maps/geo?json&ll=+ _lattitude +，+ _longitude

这将返回JSON格式的特定纬度和经度的所有细节，而你要解析由谷歌地图返回的JSON。

This will return all the details of the given latitude and longitude in JSON format,And you have to parse the JSON returned by Google map.

您可以使用下面的code：

You can use the below code:

private void getLocationFromGoogleMaps() { try { StreamConnection s = null; InputStream iStream = null; s=(StreamConnection)javax.microedition.io.Connector.open("maps.google/maps/geo?json&ll="+_lattitude+","+_longitude+getConnectionStringForGoogleMap());//&deviceside=false&ConnectionType=mds-public" HttpConnection con = (HttpConnection)s; con.setRequestMethod(HttpConnection.GET); con.setRequestProperty("Content-Type", "//text"); int status = con.getResponseCode(); if (status == HttpConnection.HTTP_OK) { iStream=s.openInputStream(); int len=(int) con.getLength(); byte[] data = new byte[8000]; byte k; String result=""; while((k = (byte)iStream.read()) != -1) { result = result+(char)k; } try { JSONObject jsonObjectMapData=new JSONObject(result); JSONArray jsonaryPlaceMark = jsonObjectMapData.getJSONArray("Placemark"); JSONObject address= jsonaryPlaceMark.getJSONObject(0); String placeName=address.getString("address"); if(placeName!=null) lblLoc.setText(address.getString("address")); else lblLoc.setText("Location information currently unavilable"); } catch (Exception e) { lblLoc.setText("location information Currently Unavilable"); } } }catch (Exception e) { System.out.println(e); lblLoc.setText("location information Currently Unavilable"); } }