如何获取设备的公共IP地址

本文介绍了如何获取设备的公共IP地址的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我找到了这个示例代码获取所有本地IP地址，但我找不到一个简单的解决方案来获取公共IP。

I found this sample code to get all local IP addresses, but I don't find an easy solution to get the public IP.

A 遗留类 Apple允许这样做 ...但它的遗产......

A legacy class from Apple allowed to do that ... but it's legacy ...

推荐答案

我用 ALSystemUtilities 。你基本上必须在外部打电话才能找到它。

I have used ALSystemUtilities in the past. You basically have to make a call externally to find this out.

+ (NSString *)externalIPAddress { // Check if we have an internet connection then try to get the External IP Address if (![self connectedViaWiFi] && ![self connectedVia3G]) { // Not connected to anything, return nil return nil; } // Get the external IP Address based on dynsns NSError *error = nil; NSString *theIpHtml = [NSString stringWithContentsOfURL:[NSURL URLWithString:@"www.dyndns/cgi-bin/check_ip.cgi"] encoding:NSUTF8StringEncoding error:&error]; if (!error) { NSUInteger an_Integer; NSArray *ipItemsArray; NSString *externalIP; NSScanner *theScanner; NSString *text = nil; theScanner = [NSScanner scannerWithString:theIpHtml]; while ([theScanner isAtEnd] == NO) { // find start of tag [theScanner scanUpToString:@"<" intoString:NULL] ; // find end of tag [theScanner scanUpToString:@">" intoString:&text] ; // replace the found tag with a space //(you can filter multi-spaces out later if you wish) theIpHtml = [theIpHtml stringByReplacingOccurrencesOfString: [ NSString stringWithFormat:@"%@>", text] withString:@" "] ; ipItemsArray = [theIpHtml componentsSeparatedByString:@" "]; an_Integer = [ipItemsArray indexOfObject:@"Address:"]; externalIP =[ipItemsArray objectAtIndex:++an_Integer]; } // Check that you get something back if (externalIP == nil || externalIP.length <= 0) { // Error, no address found return nil; } // Return External IP return externalIP; } else { // Error, no address found return nil; } }

来自ALSystemUtilities