在Spring + JSP中创建超链接的正确方法是什么?必须有一个比在< a href =...> 标记中编码更好的方法。以一个显示人物的页面为例。该URL为 people.htm 。相应的控制器从数据库中获取人员并执行可选的列排序。 JSP可能如下所示:
What's the proper way to create a hyperlink in Spring+JSP? There must be a better way than just coding in the <a href="..."> tag. Take for example a page that displays people. The URL is people.htm. The corresponding controller gets people from the database and performs optional column sorting. The JSP might look like:
<table> <tr> <td><a href="people.htm?sort=name">Name</a></td> <td><a href="people.htm?sort=age">Age</a></td> <td><a href="people.htm?sort=address">Address</a></td> </tr> ...这似乎很糟糕,因为URL 人。 htm 在JSP中是硬编码的。应该有一种方法让Spring使用 servlet.xml 中定义的URL自动构建< a> 标记。
This seems bad as the URL people.htm is hardcoded in the JSP. There should be a way to have Spring automatically build the <a> tag using the URL defined in servlet.xml.
编辑:也许我应该使用Spring表单。
Edit: Maybe I should be using a Spring form.
推荐答案唯一想到的是JSTL标准标签< c:url> 。 例如:
The only thing that comes to mind is the JSTL standard tag <c:url>. For example:
<c:url var="thisURL" value="homer.jsp"> <c:param name="iq" value="${homer.iq}"/> <c:param name="checkAgainst" value="marge simpson"/> </c:url> <a href="<c:out value="${thisURL}"/>">Next</a>现在这不会让你获得servlet映射等,但什么都不会。这不是你可以用编程方式做的事情(毕竟,servlet可以并且通常映射到一系列URL)。但这将为你逃避。
Now this won't get you servlet mapping or the like but nothing will. It's not something you could really do programmatically (after all, a servlet can and usually does map to a range of URLs). But this will take care of escaping for you.
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如何在Spring + JSP中创建超链接
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