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问题描述
如何排序日期和/或日期时间对象的列表?接受的答案此处对我无效:
How do I sort a list of date and/or datetime objects? The accepted answer here isn't working for me:
from datetime import datetime,date,timedelta a=[date.today(), date.today() + timedelta(days=1), date.today() - timedelta(days=1)] print a # prints '[datetime.date(2013, 1, 22), datetime.date(2013, 1, 23), datetime.date(2013, 1, 21)]' a = a.sort() print a # prints 'None'....what???推荐答案
您正在获得无因为 list.sort()它运行就地,这意味着它不返回任何东西,而是修改列表本身。您只需要调用 a.sort(),而不必将它分配到 a 。
You're getting None because list.sort() it operates in-place, meaning that it doesn't return anything, but modifies the list itself. You only need to call a.sort() without assigning it to a again.
有一个内置函数 sorted(),它返回列表的排序版本 - a = sorted( a)将会做你想要的。
There is a built in function sorted(), which returns a sorted version of the list - a = sorted(a) will do what you want as well.
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如何排序日期时间或日期对象的列表?
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