我刚开始使用Swift,并且想要使用如下的实例方法初始化对象的成员变量:
I am new to Swift and would like to initialize an object's member variable using an instance method like this:
class MyClass { var x: String var y: String func createY() -> String { self.y = self.x + "_test" // this computation could be much more complex } init(x: String) { self.x = x self.y = self.createY() } }基本上,不是内联 init 方法中的所有初始化代码,我想提取 y 到专用方法 createY 并在 init中调用此实例方法 createY 。但是,Swift编译器(Xcode 6.3测试版中的Swift 1.2编译器)抱怨:
Basically, instead of inlining all the initialization code in init method, I want to extract the initialization code of y to a dedicated method createY and call this instance method createY in init. However, Swift compiler (Swift 1.2 compiler in Xcode 6.3 beta) complains:
在超级.init initialize self
use of 'self' in method call 'xxx' before super.init initialize self
这里的'xxx'是实例方法的名称(createY)。
Here 'xxx' is the name of the instance method (createY).
我可以理解Swift编译器的抱怨和潜在的问题。但是,我不知道如何解决它。 Swift中正确的方法应该是在 init ?
I can understand what Swift compiler is complaining and the potential problem it wants to address. However, I have no idea how to fix it. What should be the correct way in Swift to call other instance method of initialization code in init?
中调用初始化代码的其他实例方法。使用以下技巧作为工作,但我不认为这是这个问题的惯用解决方案(和这个解决方法要求使用声明 y var 而不是 let 这也让我感到不安):
Currently, I use the following trick as work around but I don't think this is the idiomatic solution to this problem (and this workaround requires y to be declared using var instead of let which makes me feel uneasy too):
init(x: String) { self.x = x super.init() self.y = createY() }感谢任何评论。感谢。
推荐答案将 createY()转换为全局或类函数接受 x 作为参数,并返回 y 。
Convert createY() to a global or class function that accepts x as an argument and returns a y.
func createY(x: String) -> String { return x + "_test" // this computation could be much more complex }然后,通常从 init 中调用它。
Then just call it normally from your init.
class MyClass { let x: String let y: String init(x: String) { self.x = x self.y = createY(x) } }更多推荐
在Swift初始化期间调用实例方法
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