递归函数返回未定义

本文介绍了递归函数返回未定义的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个计算税收的函数.

I have a function which calculates taxes.

function taxes(tax, taxWage) { var minWage = firstTier; //defined as a global variable if (taxWage > minWage) { //calculates tax recursively calling two other functions difference() and taxStep() tax = tax + difference(taxWage) * taxStep(taxWage); var newSalary = taxWage - difference(taxWage); taxes(tax, newSalary); } else { returnTax = tax + taxWage * taxStep(taxWage); return returnTax; } }

我不明白为什么它不停止递归.

I can't see why it doesn't stop the recursion.

推荐答案

在你的职能部门:

if (taxWage > minWage) { // calculates tax recursively calling two other functions difference() and taxStep() tax = tax + difference(taxWage) * taxStep(taxWage); var newSalary = taxWage - difference(taxWage); taxes(tax, newSalary); }

您不是从函数返回值或设置 returnTax.当你不返回任何东西时，返回值是undefined.

you are not returning a value from the function or setting returnTax. When you don't return anything, the return value is undefined.

也许，你想要这个:

if (taxWage > minWage) { // calculates tax recursively calling two other functions difference() and taxStep() tax = tax + difference(taxWage) * taxStep(taxWage); var newSalary = taxWage - difference(taxWage); return taxes(tax, newSalary); }