定期创建插槽

本文介绍了定期创建插槽的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我需要根据一些歌曲创建时隙.例如，如果s如果我的播放列表中有5首歌曲，那么在此示例中，我们将根据逻辑创建插槽的时间间隔，即60/5 = 12分钟，因为此处的歌曲数为5.

I need to create time-slots according to a number of songs. For example, s if my playlist has 5 songs then we create the time-interval of slots by the logic, 60/5 = 12 minutes in this example as the number of songs was 5 here.

我还提供了开始时间和结束时间.在这里，如果我提供 start_time = 5:00 am和end_time = 6:00 am，则总歌曲数= 5

I also provide the start_time and end_time. Here if I provide start_time = 5:00 am and end_time = 6:00 am, total songs = 5

S1: 5:00 - 5:12 S2: 5:12 - 5:24 S3: 5:24 - 5:36 S4: 5:36 - 5:48 S5: 5:48 - 6:00

模型包含以下三个字段:

The Model consists of these three fields:

class SlotCreate(models.Model): from_time = models.TimeField(max_length=255, blank=True, null=True) to_time = models.TimeField(max_length=255, blank=True, null=True) songs = models.ManyToManyField('Song') labelling = models.ForeignKey('Labelling',blank=True, null=True)

我正在通过以下查询检查该插槽是否存在:

I am checking whether the slot exists with the following query:

SlotCreate.objects.filter(from_time=from_time,to_time=to_time,labelling=label).exists(): errors.append("The Slot already exists "+"\n")

这里的问题是用户是否提供:

The problem here is if the user provides:

Start_time = 5:00 End_time = 6:00 Total songs = 3

然后，由于S1，S2，S3，S4，S5已经存在，因此在上述给定的时间间隔中已经存在这些时隙.我在上面检查过的代码无法确定这种情况为

Then the slots already exist in the time interval given above as S1, S2, S3, S4, S5 are already there. The piece of code with which I check above fails to determine this case as

S1: 5:00 - 5:20 S1: 5:20 - 5:40 S1: 5:40 - 6:00

有人可以帮助我在这种情况下想念我什么吗?

Can anyone help me what am I missing here in the condition?

更新1:

我写了以下查询，但是，午夜之后无法锻炼数值.有人可以在下面的查询中提供一些帮助吗，以便我们可以检查插槽是否不重叠并在重叠时引发错误.

I have written the following query, but however, am unable to workout for values after mid-night. Can some-one please offer some help with below query so, that we can check whether the slots do not overlap and raise an error when overlapping.

SlotCreate.objects.filter(labelling = label).exclude((Q(from_time__gte=dateTimeA.time()) & Q(from_time__gte = dateTimeB.time())) | (Q(to_time__lte = dateTimeA.time()) & Q(to_time__lte = dateTimeB.time()))):

推荐答案

我认为您正在寻找类似的东西:

I think you're looking for something like this:

timeA = dateTimeA.time() timeB = dateTimeB.time() label_filter = Q(labelling=label) if timeA <= timeB: # Is either from_time OR to_time in the range? time_filter = Q(from_time__gte=timeA, from_time__lte=timeB) time_filter |= Q(to_time__gte=timeA, to_time__lte=timeB) else: # Crosses midnight time_filter = (Q(from_time__gte=timeA) | Q(from_time__lte=timeB)) time_filter |= (Q(to_time__gte=timeA) | Q(to_time__lte=timeB)) exists = SlotCreate.objects.filter(label_filter & time_filter).exists()

对于午夜条件，您基本上只是交换要比较的值.默认情况下， Q 对象执行 AND ，因此您不需要额外的Q对象就可以在第一种情况下将其拉出.

For the midnight condition, you basically just swap the values you're comparing against. The Q object does an AND by default so you don't need extra Q objects to pull it off in the first condition.

仅需注意，这显然不能处理大于24小时的范围，但是如果仅存储时间值，则您的模型不支持该范围.

Just a note, this obviously doesn't handle ranges larger than 24 hours, but your model doesn't support that if it's only storing time values.