我正在制作一个 Java 应用程序,我需要播放音频.我主要播放我的大炮射击(它是大炮射击游戏)和弹丸爆炸的小声音文件,尽管我计划播放循环背景音乐.我找到了两种不同的方法来实现这一点,但都不能像我想要的那样工作.
I'm making a java application and I need to play audio. I'm playing mainly small sound files of my cannon firing (its a cannon shooting game) and the projectiles exploding, though I plan on having looping background music. I have found two different methods to accomplish this, but both don't work how I want.
第一种方法实际上是一种方法:
The first method is literally a method:
public void playSoundFile(File file) {//java.ittoolbox/groups/technical-functional/java-l/sound-in-an-application-90681 try { //get an AudioInputStream AudioInputStream ais = AudioSystem.getAudioInputStream(file); //get the AudioFormat for the AudioInputStream AudioFormat audioformat = ais.getFormat(); System.out.println("Format: " + audioformat.toString()); System.out.println("Encoding: " + audioformat.getEncoding()); System.out.println("SampleRate:" + audioformat.getSampleRate()); System.out.println("SampleSizeInBits: " + audioformat.getSampleSizeInBits()); System.out.println("Channels: " + audioformat.getChannels()); System.out.println("FrameSize: " + audioformat.getFrameSize()); System.out.println("FrameRate: " + audioformat.getFrameRate()); System.out.println("BigEndian: " + audioformat.isBigEndian()); //ULAW format to PCM format conversion if ((audioformat.getEncoding() == AudioFormat.Encoding.ULAW) || (audioformat.getEncoding() == AudioFormat.Encoding.ALAW)) { AudioFormat newformat = new AudioFormat(AudioFormat.Encoding.PCM_SIGNED, audioformat.getSampleRate(), audioformat.getSampleSizeInBits() * 2, audioformat.getChannels(), audioformat.getFrameSize() * 2, audioformat.getFrameRate(), true); ais = AudioSystem.getAudioInputStream(newformat, ais); audioformat = newformat; } //checking for a supported output line DataLine.Info datalineinfo = new DataLine.Info(SourceDataLine.class, audioformat); if (!AudioSystem.isLineSupported(datalineinfo)) { //System.out.println("Line matching " + datalineinfo + " is not supported."); } else { //System.out.println("Line matching " + datalineinfo + " is supported."); //opening the sound output line SourceDataLine sourcedataline = (SourceDataLine) AudioSystem.getLine(datalineinfo); sourcedataline.open(audioformat); sourcedataline.start(); //Copy data from the input stream to the output data line int framesizeinbytes = audioformat.getFrameSize(); int bufferlengthinframes = sourcedataline.getBufferSize() / 8; int bufferlengthinbytes = bufferlengthinframes * framesizeinbytes; byte[] sounddata = new byte[bufferlengthinbytes]; int numberofbytesread = 0; while ((numberofbytesread = ais.read(sounddata)) != -1) { int numberofbytesremaining = numberofbytesread; sourcedataline.write(sounddata, 0, numberofbytesread); } } } catch (Exception e) { e.printStackTrace(); } }这个问题是我的整个程序停止直到声音文件完成,或者至少接近完成.
The problem with this is that my entire program stops until the sound file is finished, or at least nearly finished.
第二种方法是这样的:
File file = new File("Launch1.wav"); AudioClip clip; try { clip = JApplet.newAudioClip(file.toURL()); clip.play(); } catch (Exception e) { e.getMessage(); }我在这里遇到的问题是,每次声音文件提前结束或根本不播放取决于我放置代码的位置.
The problem I have here is that every time the sound file ends early or doesn't play at all depending on where I place the code.
他们有没有办法在没有上述问题的情况下播放声音?难道我做错了什么?非常感谢任何帮助.
Is their any way to play sound without the above mentioned problems? Am I doing something wrong? Any help is greatly appreciated.
推荐答案对于第一种方法,您必须为音频创建另一个线程.
For the first method you have to create another thread for audio.
例如像这样:
new Thread( new Runnable() { public void run() { try { // PLAY AUDIO CODE } catch (Exception e) { e.printStackTrace(); } } }).start();当然,您必须确保之前的声音不再播放.
Of course you have to make sure that previous sound isn't still playing.
更多推荐
如何在 Java 应用程序中播放音频
发布评论