我是 PHP 新手.
当有人上传的文件太大时,我想向他们显示一个警告弹出窗口并将他们重定向到前一页(反之亦然).
When someone uploads a file size too big, I want to show them a warning popup and redirect them to a previous page (or vice versa).
if(file size is too big){ ob_start(); header("location:index.php"); echo "<script type='text/javascript'>alert('Your File Size is too big!');</script>"; ob_end_flush(); exit; }上面的代码只会将我重定向到 index.php 并且不会显示任何警告弹出窗口.
This code above will just redirect me to index.php and doesn't show any warning popup.
推荐答案做类似的事情
header("Location: index.php?Message=" . urlencode($Message));然后在 index.php 上...
Then on index.php...
if (isset($_GET['Message'])) { print $_GET['Message']; }换句话说,index.php 将始终检查是否在 url 中传递了一条消息.如果有,请显示它.然后,只需在重定向中传递消息
In other words, index.php will always check if it's being passed a message in the url. If there is one, display it. Then, just pass the message in the redirect
如果你真的想使用模态弹窗,请生成 js...
if you really want to use a modal popup, generate the js...
if (isset($_GET['Message'])) { print '<script type="text/javascript">alert("' . $_GET['Message'] . '");</script>'; }请注意,如果您在消息中使用引号,除非您对其进行转义,否则这将中断
Note that this will break if you use quotes in the message unless you escape them
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PHP:弹出警报然后重定向页面
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