本文介绍了检查元素是否存在python selenium的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试通过
element=driver.find_element_by_partial_link_text("text")在Python硒中,元素并不总是存在.是否有一条快速的线检查它是否存在,并在不存在时显示NULL或FALSE代替错误消息?
in Python selenium and the element does not always exist. Is there a quick line to check if it exists and get NULL or FALSE in place of the error message when it doesn't exist?
推荐答案您可以如下实现try/except块,以检查元素是否存在:
You can implement try/except block as below to check whether element present or not:
from seleniummon.exceptions import NoSuchElementException try: element=driver.find_element_by_partial_link_text("text") except NoSuchElementException: print("No element found")或使用find_elements_...()方法之一进行检查.它应该返回空列表或与传递的选择器匹配的元素列表,但如果没有找到元素,则不会例外:
or check the same with one of find_elements_...() methods. It should return you empty list or list of elements matched by passed selector, but no exception in case no elements found:
elements=driver.find_elements_by_partial_link_text("text") if not elements: print("No element found") else: element = elements[0]更多推荐
检查元素是否存在python selenium
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