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本文介绍了找到-mtime文件日期早1个多小时的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有这样的命令，我跑每24小时现。

I have this command that I run every 24 hours currently.

find /var/www/html/audio -daystart -maxdepth 1 -mtime +1 -type f -name "*.mp3" -exec rm -f {} \;

我想运行它每隔1小时，并删除那些超过1个小时之前的文件。这是正确的：

I would like to run it every 1 hour and delete files that are older than 1 hour. Is this correct:

find /var/www/html/audio -daystart -maxdepth 1 -mtime **+0.04** -type f -name "*.mp3" -exec rm -f {} \;

我不知道我使用十进制数??

I am not sure of my use of the decimal number??

感谢您的任何修改。

或可能我只是使用 -mmin 60 ？这是正确的？

OR could I just use -mmin 60? Is this correct?

我想你的测试，好东西你建议。我得到一个空的结果。我希望所有文件的前一封 60分钟相比要删除！我怎样才能做到这一点？请问我的命令真正做到这一点？

I tried your test, good thing you suggested it. I got an empty result. I want all files OLDER than 60mins to be deleted! How can I do this?? Does my command actually do this?

推荐答案

关于 -mmin ？

find /var/www/html/audio -daystart -maxdepth 1 -mmin +59 -type f -name "*.mp3" \ -exec rm -f {} \;

从人的发现：

-mmin n File's data was last modified n minutes ago.

此外，确保先进行测试！

... -exec echo rm -f '{}' \; ^^^^ Add the 'echo' so you just see the commands that are going to get run instead of actual trying them first.