我在实体类中有两个字段:
I have two fields in an entity class:
contactType 具有PBX,GSM,TEL和FAX之类的值
contactType has values like PBX, GSM, TEL and FAX
我想要一种评分机制,以便首先获取最匹配的数据,然后是PBX,TEL,GSM和FAX.
I want a scoring mechanism as to get the most matching data first then PBX, TEL, GSM and FAX.
得分:
- 在 EstablishmentName 上首先获取最匹配的数据
- 在 contactType 上先获取PBX,然后再获取TEL等
- On establishmentName to get the most matching data first
- On contactType to get first PBX then TEL and so on
我的最终查询是:
(+企业名称:kamran〜1 ^ 2.5 +(contactType:PBX ^ 2.0 contactType:TEL ^ 1.8 contactType:GSM ^ 1.6 contactType:FAX ^ 1.4))
(+establishmentName:kamran~1^2.5 +(contactType:PBX^2.0 contactType:TEL^1.8 contactType:GSM^1.6 contactType:FAX^1.4))
但它不返回结果.
我的问题是,如何在不同的值基础上增加特定字段?
我们可以对两个不同的字段使用以下查询:
We can use the following query for two different fields:
Query query = qb.keyword() .onField( field_one).boostedTo(2.0f) .andField( field_two) .matching( searchTerm) .createQuery();但是我需要在其值上增加一个字段,就像我的情况是 contactType .
But i need to boost a field on its values as in my case it is contactType.
我的数据集: (企业名称:演唱会装饰,联系人类型:GSM), (机构名称:Elissa Concert,联系人类型:TEL), (店名:Yara Concert,contactType:FAX), (店名:E Concept,联系类型:TEL), (EstablishmentName:Infinity Concept,contactType:FAX), (名称:SD概念,contactType:PBX), (企业名称:Broadcom技术概念,contactType:GSM), (EstablishmentName:概念商人,contactType:PBX)
My dataset: (establishmentName : Concert Decoration, contactType : GSM), (establishmentName : Elissa Concert, contactType : TEL), (establishmentName : Yara Concert, contactType : FAX), (establishmentName : E Concept, contactType : TEL), (establishmentName : Infinity Concept, contactType : FAX), (establishmentName : SD Concept, contactType : PBX), (establishmentName : Broadcom Technical Concept, contactType : GSM), (establishmentName : Concept Businessmen, contactType : PBX)
通过搜索term = concert(对EstablishmentName进行模糊查询),它应该向我返回以下列表: (店名:Elissa Concert,contactType:TEL)
By searching the term=concert(fuzzy query on establishmentName), it should return me the list as below: (establishmentName : Elissa Concert, contactType : TEL)
[term = concert,完全匹配,因此通过保持 订购为PBX,TEL,GSM和FAX]
[term=concert, exact matching so it will be on top by keeping the order as PBX, TEL, GSM and FAX]
(企业名称:演唱会装饰,contactType:GSM)
(establishmentName : Concert Decoration, contactType : GSM)
[term = concert,完全匹配并保持顺序为PBX,TEL, GSM和FAX]
[term=concert, exact matching and by keeping the order as PBX, TEL, GSM and FAX]
(店名:Yara演唱会,contactType:传真)
(establishmentName : Yara Concert, contactType : FAX)
[term = concert,完全匹配并保持顺序为PBX,TEL, GSM和FAX]
[term=concert, exact matching and by keeping the order as PBX, TEL, GSM and FAX]
(店名:概念商人,contactType:PBX)
(establishmentName : Concept Businessmen, contactType : PBX)
[term = concert,部分匹配并保持顺序为PBX,TEL,GSM 和传真]
[term=concert, partial matching and keeping the order as PBX, TEL, GSM and FAX]
(店名:SD概念,contactType:PBX)
(establishmentName : SD Concept, contactType : PBX)
[term = concert,部分匹配并保持顺序为PBX,TEL,GSM 和传真]
[term=concert, partial matching and keeping the order as PBX, TEL, GSM and FAX]
(企业名称:E Concept,contactType:TEL)
(establishmentName : E Concept, contactType : TEL)
[term = concert,部分匹配并保持顺序为PBX,TEL, GSM和FAX]
[term=concert, partial matching and keeping the order as PBX, TEL, GSM and FAX]
(企业名称:Broadcom技术概念,contactType:GSM)
(establishmentName : Broadcom Technical Concept, contactType : GSM)
[term = concert,部分匹配并保持顺序为PBX,TEL,GSM 和传真]
[term=concert, partial matching and keeping the order as PBX, TEL, GSM and FAX]
(店名:Infinity概念,contactType:传真)
(establishmentName : Infinity Concept, contactType : FAX)
[term = concert,部分匹配并保持顺序为PBX,TEL,GSM 和传真]
[term=concert, partial matching and keeping the order as PBX, TEL, GSM and FAX]
推荐答案
据我了解,您基本上需要两阶段排序:
From what I understand you basically want a two-phase sort:
第二种方法很简单,但是第一种方法需要一些工作. 您实际上可以依靠评分来实现它.
The second sort is trivial, but the first one will require a bit of work. You can actually rely on scoring to implement it.
本质上,该想法是对多个查询进行分解,并为每个查询分配恒定的分数.
Essentially the idea would be to run a disjunction of multiple queries, and to assign a constant score to each query.
而不是这样做:
Query query = qb.keyword() .fuzzy().withEditDistanceUpTo(1) .boostedTo(2.5f) .onField("establishmentName") .matching(searchTerm) .createQuery();执行此操作:
Query query = qb.bool() .should(qb.keyword() .withConstantScore().boostedTo(100.0f) // Higher score, sort first .onField("establishmentName") .matching(searchTerm) .createQuery()) .should(qb.keyword() .fuzzy().withEditDistanceUpTo(1) .withConstantScore().boostedTo(1.0f) // Lower score, sort last .onField("establishmentName") .matching(searchTerm) .createQuery()) .createQuery();匹配的文档将是相同的,但是现在查询将分配可预测的分数:仅模糊匹配为1.0,模糊匹配为101.0(模糊查询为1,精确查询为100)完全匹配.
The matched documents will be the same, but now the query will assign predictable scores: 1.0 for fuzzy-only matches, and 101.0 (1 from the fuzzy query and 100 from the exact query) for exact matches.
这样,您可以定义排序如下:
This way, you can define the sort as follows:
fullTextQuery.setSort(qb.sort() .byScore() .andByField("contactType") .createSort());这可能不是一个非常优雅或优化的解决方案,但我认为它会起作用.
This may not be a very elegant, or optimized solution, but I think it will work.
要自定义联系人类型的相对顺序,我建议采用另一种方法:使用自定义桥到索引号,而不是"PBX"/"TEL"/等,为每个联系人类型分配所需的序号.本质上是这样的:
To customize the relative order of contact types, I would suggest a different approach: use a custom bridge to index numbers instead of the "PBX"/"TEL"/etc., assigning to each contact type the ordinal you expect. Essentially something like that:
public class Establishment { @Field(name = "contactType_sort", bridge = @FieldBridge(impl = ContactTypeOrdinalBridge.class)) private ContactType contactType; } public class ContactTypeOrdinalBridge implements MetadataProvidingFieldBridge { @Override public void set(String name, Object value, Document document, LuceneOptions luceneOptions) { if ( value != null ) { int ordinal = getOrdinal((ContactType) value); luceneOptions.addNumericFieldToDocument(name, ordinal, document); luceneOptions.addNumericDocValuesFieldToDocument(name, ordinal, document); } } @Override public void configureFieldMetadata(String name, FieldMetadataBuilder builder) { builder.field(name, FieldType.INTEGER).sortable(true); } private int getOrdinal(ContactType value) { switch( value ) { case PBX: return 0; case TEL: return 1; case GSM: return 2; case PBX: return 3; default: return 4; } } }然后重新编制索引,并进行如下排序:
Then reindex, and sort like this:
fullTextQuery.setSort(qb.sort() .byScore() .andByField("contactType_sort") .createSort());更多推荐
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