无法停止其他活动的响铃警报

本文介绍了无法停止其他活动的响铃警报的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我是android的新手，这里我正在练习我的第一个应用程序（警报应用程序）。

I am new to android ,Here I am practicing my first app (Alarm App).

我的应用程序中存在一个问题，我无法停止警报一旦触发，警报就不会停止。

I have an issue in my app that I can't stop the alarm once a alarm is triggered it's keep on ringing can't get stopped.

在我的应用中，我有2个活动和一个AlarmReceiver。

In my app I have 2 activities and a AlarmReceiver .

在AlarmActivity.java中，我已经设置了警报，到达特定时间后，Alarmreceiver.java将被触发，警报开始响起并显示唤醒屏幕。

From the AlarmActivity.java I have set the alarm ,when the specific time is reached the Alarmreceiver.java will get triggered and the alarm started to ring and showing a wakeup screen .

在WakeUpScreen.java中，我有一个停止按钮，需要停止当前的响铃警报。

From the WakeUpScreen.java I have a stop button by using that I need to stop the current ringing alarm .

我没有

AlarmActivity.java

AlarmActivity.java

public void stopAlarm(Context context) { Intent intent = new Intent(context,AlarmReceiver.class); intent.setAction("ALARM_OFF"); PendingIntent pendingIntent = PendingIntent.getBroadcast(context, mAlarmId, intent,PendingIntent.FLAG_UPDATE_CURRENT); AlarmManager alarmManager = (AlarmManager) context.getSystemService(ALARM_SERVICE); alarmManager.cancel(pendingIntent); }

我在AlarmActivity.java中有这个AlarmStop（）函数，它将被点击当我按下wakeupscreen.java中的停止按钮时。

I have this AlarmStop() function in my AlarmActivity.java which will get hit when I press the stop button in wakeupscreen.java

当我尝试调试停止过程时，调试器将stopAlarm（）函数中的所有行都移了，但是Intent不起作用，这就是为什么没有调用AlarmReceiver.java文件的原因，我的意思是，调试器移动了上述方法中的所有行，但没有调用AlarmReceiver.java

我尝试了很多方法来解决此问题，但我错过了一些我无法解决的问题。

I tried lot of ways to solve this but I missed something that I can't figured it out.

有人可以帮我停下来吗？

Can anyone help me to stop the triggered alarm and it's ringing sound .

推荐答案

您的体系结构已损坏。您无需使用 BroadcastReceiver 进行持久处理。 BroadcastReceiver 的生命周期很短，您可以用它触发其他事情。

Your architecture is broken. You don't use a BroadcastReceiver for persistent processing. A BroadcastReceiver has a very short lifecycle, you use it to trigger other things.

您已经创建了<您的 BroadcastReceiver 中的code> MediaPlayer 实例，并试图在 onReceive（）。错了您应该使用服务来管理和维护 MediaPlayer 的状态。

You've created a MediaPlayer instance in your BroadcastReceiver and are trying to control that in onReceive(). This is wrong. You should use a Service to manage and maintain the state of your MediaPlayer.

看看是否可以在Internet上找到有关如何构建这样的应用程序的HOWTO指南。

See if you can find some HOWTO guides on the Internet for how to build such an application.