在后台模式didReceiveRemoteNotification不叫

本文介绍了在后台模式didReceiveRemoteNotification不叫的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我工作的推送通知，我接收到的数据是JSON格式。我怎样才能解析JSON数据，这在下面的通知中心显示：

I am working on push notifications and the data I receive is in JSON format. How can I parse the JSON data, which is shown in the Notification Center below:

推荐答案

如果你的后台程序/前台模式调用此方法

if your app in background/foreground mode call this method

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo fetchCompletionHandler:(void (^)(UIBackgroundFetchResult result))completionHandler

如果你使用上面的方法，你将面临控制台下面的错误

if you used the above method you will face the following error in console

应用：didReceiveRemoteNotification：fetchCompletionHandler：]，但你仍然需要远程通知添加到您的支持UIBackgroundModes名单在你的Info.plist

application:didReceiveRemoteNotification:fetchCompletionHandler:], but you still need to add "remote-notification" to the list of your supported UIBackgroundModes in your Info.plist.

的要解决此问题

请按照步骤的图片

如果您在前台模式的应用程序调用此方法

if your app in foreground mode call this method

- (void)application:(UIApplication*)application didReceiveRemoteNotification:(NSDictionary*)userInfo

选择NO-2

- (void) application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo { UIApplicationState state = [application applicationState]; // user tapped notification while app was in background if (state == UIApplicationStateInactive || state == UIApplicationStateBackground) { // go to screen relevant to Notification content } else { // App is in UIApplicationStateActive (running in foreground) // perhaps show an UIAlertView } }

斯威夫特

func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]) { var state: UIApplicationState = application.applicationState() // user tapped notification while app was in background if state == .Inactive || state == .Background { // go to screen relevant to Notification content } else { // App is in UIApplicationStateActive (running in foreground) // perhaps show an UIAlertView } }