我想知道是否有一个快速/干净的方法来得到两组之间的差异?
我有:
设置< String> s1 = new HashSet< String>(); s1.add(a); s1.add(b); s1.add(c); 设置< String> s2 = new HashSet< String>(); s2.add(b);我需要像:
设置< String> diff = Something.diff(s1,s2); // diff将包含[a,c]
只是为了澄清我需要对称的区别。
解决方案可以使用 Google Guava 媒体库中的一些功能(这真的很棒,我强烈推荐!): / p>
Sets.difference(s1,s2); Sets.symmetricDifference(s1,s2);Javadocs difference()和symmetricDifference()
symmetricDifference()完全您要求的内容,但 difference()也常常有帮助。
两个方法都返回一个实时视图,但是你可以在结果集上调用 .immutableCopy()来获得一个不变的集合。如果你不想要一个视图,但需要一个set实例,你可以修改,调用 .copyInto(s3)。有关这些方法,请参见 SetView 。 p>
I'm wondering if there is a quick/clean way to get the difference between two sets ?
I have:
Set<String> s1 = new HashSet<String>(); s1.add("a"); s1.add("b"); s1.add("c"); Set<String> s2 = new HashSet<String>(); s2.add("b");I need something like:
Set<String> diff = Something.diff(s1, s2); // diff would contain ["a", "c"]
Just to clarify I need the symmetric difference.
解决方案You can use some functions from the Google Guava library (which is really great, I strongly recommend it!):
Sets.difference(s1, s2); Sets.symmetricDifference(s1, s2);Javadocs for difference() and symmetricDifference()
symmetricDifference() does exactly what you are asking for, but difference() is also often helpful.
Both methods return a live view, but you can for example call .immutableCopy() on the resulting set to get a non-changing set. If you don't want a view, but need a set instance you can modify, call .copyInto(s3). See SetView for these methods.
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