无法接收共享图像

本文介绍了无法接收共享图像-Android 6.0的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在使用 aFileChooser 即可在我的应用程序中获取共享图像。画廊中的图像可以正常工作，但是如果我在Google Chrome中使用图像说并尝试共享它，那么我的 imagePath 为null会给我NPE。

I am using the code provided by aFileChooser to get able to get the shared image inside my application. Images from the gallery work OK but if i use an image say inside Google Chrome and try to share it, it gives me a NPE as my imagePath is null.

String imagePath = getPath(getActivity(), imageUri);

我的 uri 被标识为MediaStore（并且），通常从以下代码中获取：

My uri is identified as MediaStore (and) general from this code:

else if ("content".equalsIgnoreCase(uri.getScheme())) { if (isGooglePhotosUri(uri)) return uri.getLastPathSegment(); return getDataColumn(context, uri, null, null); }

但是在 getDataColumn（）我的光标转储如下：

However inside getDataColumn() my cursor dump is as follows:

08-24 12:00:58.196 13186 13256 ReceivePhotos D Cursor is: >>>>> Dumping cursor android.content.ContentResolver$CursorWrapperInner@e110803 08-24 12:00:58.196 13186 13256 ReceivePhotos D 0 { 08-24 12:00:58.196 13186 13256 ReceivePhotos D _data=null 08-24 12:00:58.196 13186 13256 ReceivePhotos D } 08-24 12:00:58.196 13186 13256 ReceivePhotos D <<<<< 08-24 12:00:58.196 13186 13256 ReceivePhotos D Cursor column index is: 0

getDataColumn（）方法：

public static String getDataColumn(Context context, Uri uri, String selection, String[] selectionArgs) { Cursor cursor = null; final String column = "_data"; final String[] projection = { column }; try { cursor = context.getContentResolver().query(uri, projection, selection, selectionArgs,null); Log.d("ReceivePhotos", " Cursor is: " + DatabaseUtils.dumpCursorToString(cursor)); if (cursor != null && cursor.moveToFirst()) { final int column_index = cursor.getColumnIndexOrThrow(column); Log.d("ReceivePhotos", " Cursor column index is: " + column_index); return cursor.getString(column_index); } } finally { if (cursor != null) cursor.close(); } return null; }

ImageUri日志

08-24 12:07:32.780 13629 13696 ReceivePhotos D Image uri: content://com.android.chrome.FileProvider/images/screenshot/1472011649310784004280.jpg

电话&操作系统详细信息

Android 6.0.1上的Sony E5823

Sony E5823 on Android 6.0.1

推荐答案

您不能也不应该尝试获取与URI相对应的基础路径-在大多数情况下，您的应用将永远无法访问该路径本身，而只能通过URI。

You cannot and should not attempt to ever get the underlying path corresponding with a URI - in the vast majority of cases your app will never have access to the path itself, but only through the URI.

值得庆幸的是，您可以直接从URI中获取图像的二进制数据：

Thankfully, you can get the binary data of the image from the URI directly:

InputStream in; Bitmap bitmap = null; try { in = getContentResolver().openInputStream(imageUri); // You could do anything with the InputStream. // Here we'll just get the Bitmap at full size bitmap = BitmapFactory.decodeStream(in); } catch (IOException e) { // Something went wrong } finally { if (in != null) { try { in.close(); } catch (IOException ignored) {} } } // Now you have a Bitmap.