电话后退按钮可以在Web视图中使用,但是当我想从Web视图退出到应用程序时,它什么也没做. 我放了一个可以返回到应用程序的按钮,但我没有那样保留.
The phone back button works in the webview,but when I want to exit from the Webview to the application this didn't do anything. I put a button that go back to the application but I did't that remain that way.
JAVA:
package com.wiralss.adb; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.KeyEvent; import android.view.View; import android.view.View.OnClickListener; import android.view.Window; import android.webkit.WebChromeClient; import android.webkit.WebView; import android.webkit.WebViewClient; import android.widget.Button; public class about extends Activity implements OnClickListener{ WebView webView; final Activity activity = this; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); this.getWindow().requestFeature(Window.FEATURE_PROGRESS); setContentView(R.layout.instagrem); webView = (WebView) findViewById(R.id.webView1); Button B123=(Button)findViewById(R.id.button1235); B123.setOnClickListener(this); webView.getSettings().setJavaScriptEnabled(true); webView.loadUrl("www.google"); webView.setWebChromeClient(new WebChromeClient() { public void onProgressChanged(WebView view, int progress) { activity.setTitle("Loading..."); activity.setProgress(progress * 100); if(progress == 100) activity.setTitle(R.string.app_name); } }); webView.setWebViewClient(new WebViewClient() { @Override public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) { // Handle the error } @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { view.loadUrl(url); return true; } }); } @Override public void onClick(View v) { switch(v.getId()){ case R.id.button1235: Intent B = new Intent(this, MainActivity.class); startActivity(B); break; // TODO Auto-generated method stub } // TODO Auto-generated method stub } public void onBackPressed (){ if (webView.isFocused() && webView.canGoBack()) { webView.goBack(); } else { super.onBackPressed(); finish(); } } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if (keyCode == KeyEvent.KEYCODE_BACK) { webView.goBack(); return true; } return false; } }XML:
<?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="schemas.android/apk/res/android" xmlns:tools="schemas.android/tools" android:layout_width="match_parent" android:layout_height="match_parent" > <WebView android:id="@+id/webView1" android:layout_width="match_parent" android:layout_height="match_parent" /> <LinearLayout android:layout_width="match_parent" android:layout_height="match_parent" android:layout_centerHorizontal="true" android:layout_centerVertical="true" android:orientation="vertical" > <Button android:id="@+id/button1235" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_marginTop="580px" android:layout_weight="0.05" android:text="Button" /> </LinearLayout> </RelativeLayout>另一个问题. 要删除按钮,我需要删除吗?:
Another question. To remove the button I need to delete?:
Button B123=(Button)findViewById(R.id.button1); B123.setOnClickListener(this);然后?
@Override public void onClick(View v) { switch(v.getId()){ case R.id.button1: Intent B = new Intent(this, MainActivity.class); startActivity(B); break; // TODO Auto-generated method stub } // TODO Auto-generated method stub }非常感谢你
推荐答案您无需调用super.onBackPressed(),因为您可以自己控制活动的完成.
You don't need the call to super.onBackPressed() as you are controlling the finishing of your activity yourself.
同样,您实际上不需要webView.isFocused()方法调用.
Equally, you don't really need the webView.isFocused() method call.
您可以重写您的onBackPressed方法,使其看起来像这样:
You can rewrite your onBackPressed method to read like this:
public void onBackPressed() { if (webView.canGoBack()) { webView.goBack(); } else { finish(); } }对于包含button1235按钮的动机,我不太确定,是您要删除的内容吗?
I'm not too sure on your motives for including your button1235 Button, is that something you are wanting to remove?
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