我需要从日期(例如:2015/10/22)生成一周中的星期一的日期。并生成接下来几天的日期:星期一,星期二,星期三,星期四,星期五,星期六,星期日。
I need to generate a date of Monday of a week from a date (example: 2015/10/22). And generate the dates for the next days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Java中的示例:(初始日期= 2015/10 / 22)
Example in Java: (initial date = 2015/10/22)
//星期一:
date.set (Calendar.DAY_OF_WEEK, Calendar.MONDAY);//添加第二天(星期二)
// Add the next day (Tuesday)
date.add (Calendar.DATE, 1);//添加第二天(星期三):
// Add the next day (Wednesday):
date.add (Calendar.DATE, 1);如何在Python中做到这一点?
How can I do this in Python?
推荐答案在Python中使用timedelta函数更容易
Its easier in python using timedelta function
import datetime mydate = datetime.datetime(2015, 10, 22, 00, 00, 00, 00) mymondaydate = mydate - datetime.timedelta(days=mydate.weekday()) mytuesdaydate = mymondaydate + datetime.timedelta(days=1) print(mydate) print(mymondaydate) print(mytuesdaydate)技巧是使用weekday()函数。从文档开始
The trick is the use of weekday() function. From documentation
date.weekday()-以整数形式返回星期几,其中星期一为0,星期日为是6。
date.weekday() - Return the day of the week as an integer, where Monday is 0 and Sunday is 6.
因此,从当前日期中减去它得出的是该周的星期一。
So subtracting it from current date gives the date of Monday of that week
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在Python中生成日期到一周中的几天?
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