这最终会同时运行它们。我在这里做错了吗?
This ends up running both of them. Am I doing something wrong here?
推荐答案这是crontab格式:
This is the crontab format:
* * * * * | | | | | | | | | +---- Day of the Week (range: 0-6, 0 standing for Sunday) | | | +------ Month of the Year (range: 1-12) | | +-------- Day of the Month (range: 1-31) | +---------- Hour (range: 0-23) +------------ Minute (range: 0-59)Ubuntu man 5 crontab 说:
field allowed values ----- -------------- minute 0-59 hour 0-23 day of month 1-31 month 1-12 (or names, see below) day of week 0-7 (0 or 7 is Sun, or use names)因此,这应该对您有用:
So, this should work for you:
0 0 2-31 * 0 /home/ubuntu/x.h 0 0 2-31 * 1-6 /home/ubuntu/y.h我不确定为什么在周六运行7-您的系统时间是否正确且在正确的时区?
I'm not sure why 7 would run on Saturday--is your system time accurate and in the right timezone?
编辑:嗯,是的,很遗憾,您不能同时指定星期几和每月几号。从 man 5 crontab 开始:
Edit: Ah, yes, unfortunately you cannot specify both the day of the week and the day of the month. From man 5 crontab:
注意:命令的执行日期可以是由两个字段指定-每月的日期和星期几。如果两个字段都受限制(即不是*),则当任一字段与当前时间匹配时,将运行该命令。例如, 30 4 1,15 * 5会导致命令在每月的1号和15号的凌晨4:30以及每个星期五运行。但是,可以通过在命令中添加测试来获得所需的结果(请参见下面的示例CRON文件中的最后一个示例)。
Note: The day of a command's execution can be specified by two fields — day of month, and day of week. If both fields are restricted (i.e., aren't *), the command will be run when either field matches the current time. For example, ``30 4 1,15 * 5'' would cause a command to be run at 4:30 am on the 1st and 15th of each month, plus every Friday. One can, however, achieve the desired result by adding a test to the command (see the last example in EXAMPLE CRON FILE below).
因此,答案是:
0 0 2-31 * * test $(date +\%u) -eq 7 && /home/ubuntu/x.h 0 0 2-31 * * test $(date +\%u) -ne 7 && /home/ubuntu/y.h$(date'+%u') 返回1-7,代表星期一至星期日。以 echo $(date'+%u')为例。
$(date '+%u') returns 1-7 representing Monday thru Sunday. Try echo $(date '+%u') for an example.
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