本文介绍了通过推送通知打开应用程序时打开特定的ViewController的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
顾名思义,当用户通过滑动推送通知启动应用程序时,如何打开特定的ViewController?
As the title implies: how do I open a specific viewcontroller when a user starts the app by swiping on a push notification?
谢谢!
推荐答案执行以下操作,
在您的应用主视图控制器的"viewDidLoad"方法中添加观察者,
in your apps main view controller "viewDidLoad" method add an observer,
NSNotificationCenter.defaultCenter().addObserver(self, selector: "SomeNotificationAct:", name: "SomeNotification", object: nil)还要添加一个方法
func SomeNotificationAct(notification: NSNotification){ dispatch_async(dispatch_get_main_queue()) { self.performSegueWithIdentifier("NotificationView", sender: self) } }并在您的应用的Appdelegate类的"didReceiveRemoteNotification"方法中添加以下代码
and add the below code in your "didReceiveRemoteNotification" method of Appdelegate class of your app
func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]){ NSNotificationCenter.defaultCenter().postNotificationName("SomeNotification", object:nil, userInfo:someData) }更多推荐
通过推送通知打开应用程序时打开特定的ViewController
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