IOS JSON从“JSON Dict”中获取所有值。

本文介绍了IOS JSON从“JSON Dict”中获取所有值。的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有这样的数据结构：

{ "artistlist " : [ { "performer" : "Gate Zero" }, { "performer" : "nightech" }, { "performer" : "Marko Fuerstenberg" }, ] }

我用这行代码从NSString读取这个结构到NSDictionary：

I read this structure from NSString into NSDictionary with this line of code:

JSON = [NSJSONSerialization JSONObjectWithData: [[chunks objectAtIndex:1] dataUsingEncoding:NSUTF8StringEncoding] options: NSJSONReadingMutableContainers error: &e];

with： [JSON objectForKey：@artistlist] 我得到这种结构：

with: [JSON objectForKey:@"artistlist "] i get this structure:

( { performer = "Gate Zero"; }, { performer = nightech; }, { performer = "Marko Fuerstenberg"; } )

有没有什么方法可以更深入？

Is there any way to go "deeper" ?

我将如何解析生成的结构？

how would i parse the resulting Structure ?

我想直接获取值列表或访问执行者名称。如果我在tupel中有多个值，例如表演者姓名，专辑，年份，该怎么办？我如何访问这些值？

I would like to get a list of values or access performer names directly. What if i have several values in a tupel for example performer name, album, year. How would i access those values?

谢谢。

推荐答案

是的，在您拥有 [JSON objectForKey：@artistlist] 之后，您将获得 NSArray NSDictionaries （有点令人困惑！）。

Yes, after you have [JSON objectForKey:@"artistlist "], you get an NSArray of NSDictionaries (slightly confusing!).

NSArray *performersArray = [JSON objectForKey:@"artistlist"]; for (NSDictionary *performerDic in performersArray) { NSLog(@"%@", [performerDic objectForKey:@"performer"]); }

这应该产生每个表演者的名字。或者，您可以执行（NSUInteger i = 0; i< [performersArray count]; i ++）并访问 NSDictionary * performersDic = [performersArray objectAtIndex ：i] 。从那里，你可以类似地使用 [performDic objectForKey：@performer]

This should yield each performer name. Alternatively, you can do for (NSUInteger i = 0; i < [performersArray count]; i++) and access NSDictionary *performersDic = [performersArray objectAtIndex: i]. From there, you can similarly use [performsDic objectForKey:@"performer"]