将F#管道运算符(<

本文介绍了将F#管道运算符(< |，>&gt ;、<<)转换为OCaml的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在将一些F#代码转换为OCaml，例如，我看到此管道运算符<|有很多用途:

I'm converting some F# code to OCaml and I see a lot of uses of this pipeline operator <|, for example:

let printPeg expr = printfn "%s" <| pegToString expr

<|运算符显然定义为:

# let ( <| ) a b = a b ;; val ( <| ) : ('a -> 'b) -> 'a -> 'b = <fun>

我想知道为什么他们要麻烦地在F#中定义和使用此运算符，仅仅是为了避免出现这样的括号吗?:

I'm wondering why they bother to define and use this operator in F#, is it just so they can avoid putting in parens like this?:

let printPeg expr = Printf.printf "%s" ( pegToString expr )

据我所知，这就是上面的F#代码到OCaml的转换，对吗?

As far as I can tell, that would be the conversion of the F# code above to OCaml, correct?

此外，我如何在Ocaml中实现F#的<<和>>运算符?

Also, how would I implement F#'s << and >> operators in Ocaml?

(|>运算符似乎只是:let ( |> ) a b = b a ;;)

推荐答案

直接从 F#源:

let inline (|>) x f = f x let inline (||>) (x1,x2) f = f x1 x2 let inline (|||>) (x1,x2,x3) f = f x1 x2 x3 let inline (<|) f x = f x let inline (<||) f (x1,x2) = f x1 x2 let inline (<|||) f (x1,x2,x3) = f x1 x2 x3 let inline (>>) f g x = g(f x) let inline (<<) f g x = f(g x)