在Swift 2.0中解析JSON

本文介绍了在Swift 2.0中解析JSON的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试从服务器api解析JSON数据. json:

I'm trying to parse JSON data from a server api. The json :

[ {"interest": { "title":"Sport", "sub":[ "painting", "photography", "museum"] } }, {"interest": { "title": "music", "sub": [ "rock", "classic", "techno"] } }]

从文件中获取代码以进行测试以分析它的代码:

The code to get it from a file just to test to parse it :

do{ let path = NSBundle.mainBundle().pathForResource("MainInterest", ofType: "json") let jsonData = NSData(contentsOfFile: path!) let jsonResult:NSArray! = try NSJSONSerialization.JSONObjectWithData(jsonData! , options: NSJSONReadingOptions.MutableContainers) as! NSArray } catch let error as NSError { print(error) }

我可以使用:

print(jsonResult)

但是我不能访问多个级别，这是第一个级别:

But I can't access more than one level, here is the first level :

if let a = jsonResult { print(a[0]["interest"]) }

然后我可以从文件中获取第一个对象，但是我想访问 jsonResult [0] ["interest"] ["title"](== Sport)或jsonResult [0 ] ["interest"] ["sub"] [2](==摄影)，但是我的这种错误构建失败:

I can then get my first object from my file, but I would like to access jsonResult[0]["interest"]["title"] (==Sport) or jsonResult[0]["interest"]["sub"][2] (== photography) but I have this kind of error build failed:

Cannot subscript a value of type 'AnyObject?!' with an index of type 'String' Cannot subscript a value of type 'AnyObject?!' with an index of type 'Int'

能请你帮我吗?我真的很困惑，我认为苹果文档在这一点上不是很明确.而且我不想使用swiftyJson等框架.

Could you please help me ? I'm really stuck and the apple doc is not so explicite on this point I think. And I don't want to use framework like swiftyJson etc.

非常感谢！ 本

已解决(感谢@maxpovver):

Solved with (thanks @maxpovver) :

//To Get Title let title = (((self.interests as NSArray)[0] as? NSDictionary)?["interest"] as? NSDictionary)?["title"] as? NSString print(title) //To Get Sub let sub = ((((self.interests as NSArray)[0] as? NSDictionary)?["interest"] as? NSDictionary)?["sub"] as! NSArray)[1] as! NSString

推荐答案

答案

//To Get Title let title = (((self.interests as Array)[0] as? Dictionary)?["interest"] as? Dictionary)?["title"] as? String print(title) //To Get Sub let sub = ((((self.interests as Array)[0] as? Dictionary)?["interest"] as? Dictionary)?["sub"] as! Array)[1] as! String

还可以提高可读性:

let firstInterest = ((self.interests as Array)[0] as? Dictionary)?["interest"] as? Dictionary)? let title = firstInterest?["title"] as? String let sub = (firstInterest?["sub"] as! Array)[1] as! String

如果没有一些额外的库，因为swift不支持动态类型，您将永远无法简化.

You'll never be ablo to simplify that without some extra libraries as swift does not support dynamic types.