本文介绍了从SimpleXMLElement对象获取价值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这样的东西:
$url = "ws.geonames/findNearbyPostalCodes?country=pl&placename="; $url .= rawurlencode($city[$i]); $xml = simplexml_load_file($url); echo $url."\n"; $cityCode[] = array( 'city' => $city[$i], 'lat' => $xml->code[0]->lat, 'lng' => $xml->code[0]->lng );应该从地名下载XML.如果我执行print_r($xml)我会得到:
It's supposed to download XML from geonames. If I do print_r($xml) I get :
SimpleXMLElement Object ( [code] => Array ( [0] => SimpleXMLElement Object ( [postalcode] => 01-935 [name] => Warszawa [countryCode] => PL [lat] => 52.25 [lng] => 21.0 [adminCode1] => SimpleXMLElement Object ( ) [adminName1] => Mazowieckie [adminCode2] => SimpleXMLElement Object ( ) [adminName2] => Warszawa [adminCode3] => SimpleXMLElement Object ( ) [adminName3] => SimpleXMLElement Object ( ) [distance] => 0.0 )正如您所见,我做$xml->code[0]->lat,它返回一个对象.我如何获得价值?
I do as you can see $xml->code[0]->lat and it returns an object. How can i get the value?
推荐答案您必须将simpleXML对象转换为字符串.
You have to cast simpleXML Object to a string.
$value = (string) $xml->code[0]->lat;更多推荐
从SimpleXMLElement对象获取价值
发布评论