本文介绍了如何在Swift 3中使用带有FloatingPoint值的sin(_:)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
import Foundation public func sine< T:FloatingPoint> (_ x:T) - > T { return sin(x)} //错误:无法用类型为'(T)'的参数列表调用'sin'
有没有办法解决这个问题? 非常感谢
解决方案您可以创建一个接受FloatingPoint类型的sin方法,如下所示:
pre $ import UIKit func sin< T:FloatingPoint>(_ x:T) - > T { switch x { case let x as double: return sin(x)as? T? 0 的情况下让x作为CGFloat:返回sin(x)as? T? 0 case让x为浮点数:返回sin(x)as? T? 0 default: return 0 as T } }另一个选择是向FloatingPoint类型添加一个方法或一个计算的属性扩展如下:
扩展FloatingPoint { var sin:self { switch self { case let x as Double: return UIKit.sin(x)as?自我? 0 case让x为CGFloat:返回UIKit.sin(x)as?自我? 0 大小写为x浮点数:返回UIKit.sin(x)as?自我? 0 default: return 0 as Self } } }import Foundation public func sine <T: FloatingPoint > (_ x: T ) -> T{ return sin(x) } // Error: Cannot invoke 'sin' with an argument list of type '(T)'
Is there a way around this? Many thanks.
解决方案You can make a sin method that accepts FloatingPoint type also as follow:
import UIKit func sin<T: FloatingPoint>(_ x: T) -> T { switch x { case let x as Double: return sin(x) as? T ?? 0 case let x as CGFloat: return sin(x) as? T ?? 0 case let x as Float: return sin(x) as? T ?? 0 default: return 0 as T } }Another option is adding a method or a computed property extension to FloatingPoint type as follow:
extension FloatingPoint { var sin: Self { switch self { case let x as Double: return UIKit.sin(x) as? Self ?? 0 case let x as CGFloat: return UIKit.sin(x) as? Self ?? 0 case let x as Float: return UIKit.sin(x) as? Self ?? 0 default: return 0 as Self } } }
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