如何获取JSON响应数组的所有索引值？

本文介绍了如何获取JSON响应数组的所有索引值？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我需要获取JSON响应数组的所有索引值并维护单独的数组。在下面我发布了我的JSON响应，我想让控制台输出看起来如下所示。请帮帮我。

I need to get JSON response array all indexes values and maintain separate array. Here below I have posted my JSON response and I wanted to get console output looks like below also. Please help me.

response : [ { A = [ { name : "sons"; age = [ 4 ]; }, { name : "rondo"; age = [ 2 ]; }, ]; } ]

我需要单独存储单独的数组值看起来像控制台输出下面

I need to store separate array separate values looks like below console output

2014-09-18 10:24:39.461 Myapp[1133:60b] RESULT : { name = "sons"; age = 4; } 2014-09-18 10:24:39.462 Myapp[1133:60b] RESULT : { name = "rondo"; age = 2; }

下面我试过但我知道我只能获得第0个指数值但是我需要从JSON响应数组中获取所有索引值：

Here below I tried but I Know I can get only 0th index value but I need to get all index value from JSON response array:

myvalue = [NSString stringWithFormat:@"%@",[[[[responsData objectAtIndex:0] valueForKey:@"A"] objectAtIndex:0] valueForKey:@"name"]];

推荐答案

如果要获取所有对象，请获取数组然后通过根据数组计数迭代for循环将结果存储在另一个数组中。

if you want to get all objects, get the array using the respective key.Then store the result in another array by iterating the for loop according to array count.

NSArray *recordsArr = [[responsedata objectAtIndex:0] valueForKey:@"A"]; NSMutableArray *resultArray = [[NSMutableArray alloc] init]; for (int i = 0; i < [recordsArr count]; i ++) { NSMutableDictionary *recordDict = [[NSMutableDictionary alloc] init]; [recordDict setObject:[[recordsArr objectAtIndex:i] valueForKey:@"name"] forKey:@"name"]; [recordDict setObject:[[[recordsArr objectAtIndex:i] valueForKey:@"age"] objectAtIndex:0] forKey:@"age"]; [resultArray addObject:recordDict]; } NSLog(@"%@",resultArray);

输出：

2014-09-18 12:49:22.047 testprj[1044:60b] ( { age = 4; name = sons; }, { age = 2; name = rondo; } )