随机密码生成器Swift 3?

本文介绍了随机密码生成器Swift 3?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在为iOS构建一个随机密码生成器.其中，按钮会生成一个具有用户选择特征的随机密码(例如，用于打开或关闭大小写字母，字符和符号等的开关).

I'm building a random password generator for iOS. In it, a button generates a random password that has characteristics chosen by the user (e.g. switches to turn on or off lowercase and uppercase letters, characters and symbols, and so on).

UI看起来不错，其余代码运行顺利，但是我无法获得真正生成随机字母数字字符串的按钮.我有一个带有占位符文本(您的密码")的标签，当按下按钮时，该文本应更新为随机字符串，但出现编译器错误:未解析的标识符'length'的使用"

The UI looks great, the rest of the code is working smoothly, but I can't get my button to actually generate a random alphanumerical string. I have a label with some placeholder text ("Your Password") that should have its text updated to a random string when the button is pushed, but I am getting a compiler error: "unresolved use of identifier 'length'"

这是按钮的当前代码:

@IBAction func generatePassword(_ sender: UIButton) { let randomPasswordArray: NSString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890" let len = UInt32(randomPasswordArray.length) var randomPassword = "" for _ in 0 ..< length { let rand = arc4random(len) var nextChar = randomPasswordArray.character(at: Int(rand)) randomPassword += NSString(characters: &nextChar, length: 1) as String } passwordLabel.text = "randomPassword" }

谢谢！

推荐答案

首先使用允许密码的字符创建一个数组

First create an array with your password allowed characters

let passwordCharacters = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890".characters)

然后选择密码长度

let len = 8

定义和空字符串密码

var password = ""

创建循环以粘贴您的随机字符

create a loop to gennerate your random characters

for _ in 0..<len { // generate a random index based on your array of characters count let rand = arc4random_uniform(UInt32(passwordCharacters.count)) // append the random character to your string password.append(passwordCharacters[Int(rand)]) } print(password) // "V3VPk5LE"

快捷键4

您还可以使用map代替标准循环:

You can also use map instead of a standard loop:

let pswdChars = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") let rndPswd = String((0..<len).map{ _ in pswdChars[Int(arc4random_uniform(UInt32(pswdChars.count)))]}) print(rndPswd) // "oLS1w3bK\n"

Swift 4.2

使用新集合的 randomElement()方法:

let len = 8 let pswdChars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890" let rndPswd = String((0..<len)pactMap{ _ in pswdChars.randomElement() }) print(rndPswd) // "3NRQHoiA\n"