我知道这个问题已经问过很多次了.但是我仍然是一个新手,似乎我无法反序列化从get请求获得的json数组.
I know this question has been asked many times. But i'm still a newbie and it seems like I can't deserialize the json array I got from a get request.
这是我的代码:
Activity.cs
var getResponse = RequestClass.GetChargingPointsData(pathUrl, currentToken); System.Diagnostics.Debug.WriteLine("My GETresponse: " + getResponse); //CharchingPointClass getCPDetail = JsonConvert.DeserializeObject<CharchingPointClass> (getResponse); //var getCPDetail = JsonConvert.DeserializeObject<CharchingPointClass> (getResponse); //List<CharchingPointClass> getCPDetail = (List<CharchingPointClass>)JsonConvert.DeserializeObject(getResponse, typeof(List<CharchingPointClass>)); CharchingPointClass result = (CharchingPointClass)JsonConvert.DeserializeObject(getResponse, typeof(CharchingPointClass)); System.Diagnostics.Debug.WriteLine("My longitudes: " + result.lat);注释中的代码也不适用于我...
The codes in comment also didn't work for me...
CharchingPointClass.cs
public class CharchingPointClass { public string _id { get; set; } public double price { get; set; } public string type { get; set; } public string model { get; set; } public string modelID { get; set; } public double lat { get; set; } public double lng { get; set; } public string address { get; set; } public int __v { get; set; } public string modified_at { get; set; } public string created_at { get; set; } public CharchingPointClass () { } }更新: json
UPDATE: json
[ { "_id": "56d98506a7012ee0001bc42c", "price": 135.5, "type": "Type2", "model": "id11", "modelID": "Model1", "lat": 15.5, "long": 123.56, "address": "Van Vaerenberghstraat 11, 2600 Berchem", "__v": 0, "modified_at": "2016-03-04T15:58:44.142Z", "created_at": "2016-03-04T12:52:22.719Z" }, { "_id": "56d98909a7012ee0001bc42d", "price": 5000, "type": "TypeBart", "model": "MijnModel", "modelID": "Home-1-ABC", "lat": 4.427484, "long": 51.197772, "address": "Van Vaerenberghstraat 11, 2600 Berchem", "__v": 0, "modified_at": "2016-03-04T13:09:29.173Z", "created_at": "2016-03-04T13:09:29.172Z" }, { "_id": "56d98987a7012ee0001bc42e", "price": 22.22, "type": "Type222", "model": "aaa", "modelID": "abc1223456", "lat": 4.442229, "long": 51.141699, "address": "Veldkant 37, 2550 Kontich", "__v": 0, "modified_at": "2016-03-04T13:11:35.466Z", "created_at": "2016-03-04T13:11:35.466Z" }, { "_id": "56d989d0a7012ee0001bc42f", "price": 0.17, "type": "TypeNG", "model": "ModelDeborah", "modelID": "ModelIDDeb", "lat": 4.418491, "long": 51.222212, "address": "Osystraat 53, 2060 Antwerpen", "__v": 0, "modified_at": "2016-03-04T13:12:48.706Z", "created_at": "2016-03-04T13:12:48.706Z" }]
错误消息:
{Newtonsoft.Json.JsonSerializationException:无法将当前JSON对象(例如{"name":"value"})反序列化为类型'iChargeClassTest.CharchingPointClass',因为该类型需要JSON数组(例如[1,2,3 ])正确反序列化. 要解决此错误,可以将JSON更改为JSON数组(例如[1,2,3]),也可以将反序列化类型更改为数组,或者将实现集合接口的类型(例如ICollection,IList)更改为List,例如可以从中进行反序列化的List JSON array.JsonObjectAttribute也可以添加到类型中,以强制其从JSON数组反序列化.}
{Newtonsoft.Json.JsonSerializationException: Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'iChargeClassTest.CharchingPointClass' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly. To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type an array or a type that implements a collection interface (e.g. ICollection, IList) like List that can be deserialized from JSON array.JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON array.}
有人可以帮我吗?
非常感谢您的帮助:)
推荐答案您必须使用该行进行反序列化.
You have to use the line for Deserializing.
var result=JsonConvert.DeserializeObject<List<CarchingPointClass>>(inputString)班级将是
public class CarchingPointClass { public string _id { get; set; } public double price { get; set; } public string type { get; set; } public string model { get; set; } public string modelID { get; set; } public double lat { get; set; } [JsonProperty("long")] public double lng { get; set; } public string address { get; set; } public int __v { get; set; } public string modified_at { get; set; } public string created_at { get; set; } }更多推荐
无法反序列化json数组
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