将自定义对象与自定义对象数组存储在Firebase中:Swift

本文介绍了将自定义对象与自定义对象数组存储在Firebase中:Swift的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如何使用Swift在Firebase Realtime数据库中实现此设置:

How would I achieve this setup in Firebase Realtime Database with Swift:

数据库层次结构

当前，我通过将较大的元素(具有属性familyKey，geofences和phoneNumbers)存储为自定义对象来实现此目的.此外，geofences属性本身是自定义对象的数组.我得到了NSException以描述的方式执行此操作.我还能怎么做呢?

Currently, I am doing this by storing the larger element (with properties familyKey, geofences, and phoneNumbers) as a custom object. Also, the geofences property itself is an array of custom objects. I get an NSException doing this in the described fashion. How else would I go about doing this?

var tempGeofences = [GeofenceData]() tempGeofences.append(GeofenceData(name: "Hello WOrld", latitude: 0, longitude: 0, radius: 1000)) let familyKey:String = String(Int.random(in: 1000...99999)) let uid:String = Auth.auth().currentUser!.uid let phoneNumber = "1111111111" let parent = Parent(phoneNumber: phoneNumber, familyKey: familyKey, geofences: tempGeofences) databaseRef.child(uid).setValue(parent)

在此行上引发了NSException:

The NSException is thrown on this line:

databaseRef.child(uid).setValue(parent)

父类:

import Foundation public class Parent { var phoneNumber: String? var familyKey: String? var geofences: [GeofenceData]? init() { self.phoneNumber = "" self.familyKey = "" self.geofences = nil } init(phoneNumber: String?, familyKey: String?, geofences:[GeofenceData]) { self.phoneNumber = phoneNumber self.familyKey = familyKey self.geofences = geofences } public func getPhoneNumber() -> String { return phoneNumber! } public func getFamilyKey() -> String { return familyKey! } public func getGeofences() -> [GeofenceData] { return geofences! } // left off here, trying to send geofence object to firebase public func toDictionary() -> Any { return ["familyKey": familyKey, "geofences": geofences, "phoneNumber": phoneNumber] }

}

和GeofenceData类:

And the GeofenceData class:

import Foundation import Firebase public class GeofenceData { var name: String? var latitude: Double? var longitude: Double? var radius: Float? init() { } init(name: String?, latitude: Double, longitude: Double, radius: Float) { self.name = name self.latitude = latitude self.longitude = longitude self.radius = radius } // left off here, trying to send geofence object to firebase public func toDictionary() -> Any { return ["name": name, "latitude": latitude, "longitude": longitude, "radius": radius] } public func getName() -> String { return name! } public func getLatitude() -> Double { return latitude! } public func getLongitude() -> Double { return longitude! } public func getRadius() -> Float { return radius! } public func setName(name: String?) { self.name = name } public func saveToFirebase(reference: DatabaseReference) { let dict = ["name": name, "latitude": latitude, "longitude": longitude, "radius": radius] as Any reference.child("geofences").child("0").setValue(dict) }

}

推荐答案

父项不是Firebase识别的对象，因此会引发错误.

Parent is not an object that Firebase recognizes so it throws an error.

Firebase指南阅读和阅读写入数据显示了可以写入的四种对象.字符串，数字，字典，数组.

The Firebase guide Reading & Writing Data shows the four types of objects that can be written; String, Number, Dictionary, Array.

一种解决方案是在类中构建一个函数，以返回要写入的数据.

One solution is to build a function into the class that returns the data you want to write.

public class Parent { var phoneNumber: String? var familyKey: String? var geofences: [GeofenceData]? init() { self.phoneNumber = "" self.familyKey = "" self.geofences = nil } //other init functions func getParentDict() -> [String: Any] { let geoDict = ["name": name, "latitude": latitude, "longitude": longitude, "radius": radius ] let zeroNode = ["0": geoDict] let dictForFirebase: [String: Any] = [ "phoneNumber": phoneNumber, "familyKey": familyKey, "geofences": zeroNode ] return dictForFirebase } }

在实践中

var tempGeofences = [GeofenceData]() tempGeofences.append(GeofenceData(name: "Hello WOrld", latitude: 0, longitude: 0, radius: 1000)) let familyKey:String = String(Int.random(in: 1000...99999)) let uid:String = Auth.auth().currentUser!.uid let phoneNumber = "1111111111" let parent = Parent(phoneNumber: phoneNumber, familyKey: familyKey, geofences: tempGeofences) let parentDict = parent.getParentDict databaseRef.child(uid).setValue(parentDict)

但是，令人担忧的是以"0"作为键的子节点.看起来您可能正在使用数组.如果有很好的理由，但是在NoSQL数据库中使用数组通常会有更好的选择.请参阅旧版但仍然准确的Firebase帖子，名为 Arrays Evil

However, one concern is the child node with "0" as the key. That looks like you may be using an array. If there's a good reason that's fine but there are usually much better alternatives to using array's in NoSQL databases. See the legacy but still accurate Firebase post called Arrays Are Evil

每个注释/问题如何在"0"节点之后添加另一个子节点"

Per a comment/question 'how to add another child node following the "0" node"

假设我们知道父节点qSaEE ...，让我们添加一个"1"节点

Assume we know the parent node, qSaEE..., lets add a "1" node

let parentNode = "qSaEE..." let geofenceRef = firebaseRef.child(parentNode).child("geofences") let geoDict = ["name": name, "latitude": latitude, "longitude": longitude, "radius": radius ] let oneNode = ["1": geoDict] geofenceNode.setValue(oneNode)