本文介绍了如何使用引导类警报显示成功消息PHP代码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在使用PHP更新或插入记录时,我需要显示成功消息
I need to display Success Message while update or insert records in using PHP
这是我的HTML代码
<form action='a.php' methord='post'> // alert message here <div class="alert"> <a class="close" data-dismiss="alert"><i class="icon-remove"></i></a> <strong><?php echo $message; ?></strong> </div> <input type="text" class="form-control" style="height:27px;" name="name"\> <input type="email" class="form-control" style="height:27px;" name="email"\> <input type="tel" class="form-control" style="height:27px;" name="mobile"\> <input type="submit" name="user_details" class="btn btn-danger" value="Submit" /> </form>Php代码(a.php):
Php Code (a.php):
if(isset($_POST['user_details'])) { $name = $_POST['name']; $email = $_POST['email']; $mobile= $_POST['mobile']; $sql = mysql_query("update user_details set name='$name', email='$email', mobile='$mobile'"); if($sql==true) { $message = 'Success'; } else { echo ''.mysql_error(); } }推荐答案
HTML
HTML
<div class="form-group"> <div class="col-sm-10 col-sm-offset-2"> <?php echo $result; ?> </div> </div>
PHP
PHP
if ($error == false) { $result='<div class="alert alert-success">Thank You! I will be in touch</div>'; }else { $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later</div>'; }
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如何使用引导类警报显示成功消息PHP代码
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