在Jackson / Jersey JAVA上发布带有多个参数JSON和String的请求

本文介绍了在Jackson / Jersey JAVA上发布带有多个参数JSON和String的请求的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我使用Jersey / Jackson创建了一个休息api，效果很好。我想调整我的POST方法以接收除了作为JSON接收的POJO之外的字符串标记。我已经调整了我的一个方法：

I've created a rest api using Jersey/Jackson and it works well. I want to adjust my POST methods to receive a string token in addition to the POJO they are receiving as JSON. I've adjusted one of my methods like so:

@POST @Path("/user") @Consumes(MediaType.APPLICATION_JSON) public Response createObject(User o, String token) { System.out.println("token: " + token); String password = Tools.encryptPassword(o.getPassword()); o.setPassword(password); String response = DAL.upsert(o); return Response.status(201).entity(response).build(); }

我想调用该方法，但无论出于何种原因令牌无论我尝试什么，打印到null。这是我写的发送邮件请求的客户端代码：

I want to call that method, but for whatever reason token prints to null no matter what I try. Here is the client code I've written to send the post request:

public String update() { try { com.sun.jersey.api.client.Client daclient = com.sun.jersey.api.client.Client .create(); WebResource webResource = daclient .resource("localhost:8080/PhizzleAPI/rest/post/user"); User c = new User(id, client, permission, reseller, type, username, password, name, email, active, createddate, lastmodifieddate, token, tokentimestamp); JSONObject j = new JSONObject(c); ObjectMapper mapper = new ObjectMapper(); String request = mapper.writeValueAsString(c) + "&{''token'':,''" + "dog" + "''}"; System.out.println("request:" + request); ClientResponse response = webResource.type("application/json") .post(ClientResponse.class, request); if (response.getStatus() != 201) { throw new RuntimeException("Failed : HTTP error code : " + response.getStatus()); } System.out.println("Output from Server .... \n"); String output = response.getEntity(String.class); setId(UUID.fromString(output)); System.out.println("output:" + output); return "" + output; } catch (UniformInterfaceException e) { return "failue: " + e.getMessage(); } catch (ClientHandlerException e) { return "failue: " + e.getMessage(); } catch (Exception e) { return "failure: " + e.getMessage(); } }

任何帮助都将不胜感激。

Any help would be greatly appreciated.

推荐答案

这不是JAX-RS的工作方式。 POST请求的主体将被封送到带注释的资源方法的第一个参数（在这种情况下，进入 User 参数）。你有两个选择来解决这个问题：

This is not the way JAX-RS works. The body of your POST request will get marshaled to the first argument of your annotated resource method (in this case, into the User argument). You have a couple options to get around this:

创建一个包含User对象和令牌的包装器对象。在客户端和服务器之间来回发送。

在您的URL上将令牌指定为查询参数，并在服务器端以 @QueryParam 。

将标记添加为标头参数，并在服务器端以 @HeaderParam 的形式访问它。

Create a wrapper object containing both a User object and token. Send that back and forth between your client and server.

Specify the token as a query parameter on your URL and access it on the server side as a @QueryParam.

Add the token as a header parameter and access it on the server side as a @HeaderParam.

示例 - 选项1

class UserTokenContainer implements Serializable { private User user; private String token; // Constructors, getters/setters }

示例 - 选项2

客户：

WebResource webResource = client. resource("localhost:8080/PhizzleAPI/rest/post/user?token=mytoken");

服务器：

@POST Path("/user") @Consumes(MediaType.APPLICATION_JSON) public Response createObject(@QueryParam("token") String token, User o) { System.out.println("token: " + token); // ... }

示例 - 选项3

客户：

ClientResponse response = webResource .type("application/json") .header("Token", token) .post(ClientResponse.class, request);

服务器：

@POST Path("/user") @Consumes(MediaType.APPLICATION_JSON) public Response createObject(@HeaderParam("token") String token, User o) { System.out.println("token: " + token); // ... }